K J 6 2
J 6
J 10 9 7 3
Q J
Q 10 7 4 K 7 3 A K 8 4 K 5
![[W - E]](t.gif)
8 5 9 8 5 4 5 2 9 7 6 4 3
A
A 9 3 A Q 10 2 Q 6 A 10 8 2
|
| K J 6 2 J 6 J 10 9 7 3 Q J
| |
| Q 10 7 4 K 7 3 A K 8 4 K 5
|
| 8 5 9 8 5 4 5 2 9 7 6 4 3
|
| Lead: A
| A 9 3 A Q 10 2 Q 6 A 10 8 2 |
Made 4 —— NS +430 ——
I opened as south 1NT and finally became declarer in 3NT. West led the diamond ace and shifted to a small heart. The heart jack in dummy held the trick and I continued with the club queen. West took the king and returned a club. A diamond to my queen held the trick.
I guess I should have unblocked the diamond queen, because now the diamonds were blocked. Now I needed a second entry to dummy to make the diamonds high. I played a spade to the jack and continued diamonds. Because the spade queen was onside I easily made 10 tricks.
So what is the problem? Well,... I should have made 11 tricks! After the jack of spades held, I should have continued a spade to my ace and continued clubs. This would then be the ending:
|
| K 6 6 J 10 -
| |
| Q 10 K 7 K -
|
| Immaterial |
| 3 A Q 10 - A |
On the club ace west would be squeezed in 3 suits! A spade or diamond discard allows me to cross to the table and squeeze west again with the new winner, and if west shortens himself in hearts, I have two extra winners in the heart suit.
Although I couldn't foresee this ending, I should have played it this way. If the spades were 3-3, I would have a red suit squeeze against west for 11 tricks. And if the spades were 2-4 (with the fourcard in east), I could always throw west in with a diamond for a return in my heart tenace for 10 tricks.