We consider the system AotoYamada_05__017.

  Alphabet:

    uncurry : [a -> b -> c * a * b] --> c 

  Rules:

    uncurry(f, x, y) => f x y 

This AFS is converted to an AFSM simply by replacing all free variables by meta-variables (with arity 0).

We use the dependency pair framework as described in [Kop12, Ch. 6/7], with dynamic dependency pairs.

After applying [Kop12, Thm. 7.22] to denote collapsing dependency pairs in an extended form, we thus obtain the following dependency pair problem (P_0, R_0, minimal, formative):

  Dependency Pairs P_0:

    0] uncurry#(F, X, Y) =#> F(X, Y)   

  Rules R_0:

    uncurry(F, X, Y) => F X Y 

Thus, the original system is terminating if (P_0, R_0, minimal, formative) is finite.

We consider the dependency pair problem (P_0, R_0, minimal, formative).

This combination (P_0, R_0) has no formative rules!  We will name the empty set of rules:R_1.

By [Kop12, Thm. 7.17], we may replace the dependency pair problem (P_0, R_0, minimal, formative) by (P_0, R_1, minimal, formative).

Thus, the original system is terminating if (P_0, R_1, minimal, formative) is finite.

We consider the dependency pair problem (P_0, R_1, minimal, formative).

We will use the reduction pair processor [Kop12, Thm. 7.16].  As the system is abstraction-simple and the formative flag is set, it suffices to find a tagged reduction pair [Kop12, Def. 6.70].  Thus, we must orient:

  uncurry#(F, X, Y) >? F(X, Y) 

We apply [Kop12, Thm. 6.75] and use the following argument functions:

  pi( uncurry#(F, X, Y) ) = #argfun-uncurry##(F X Y) 

We orient these requirements with a polynomial interpretation in the natural numbers.

The following interpretation satisfies the requirements:

  #argfun-uncurry## = \y0.1 + y0 
  uncurry# = \G0y1y2.0 

Using this interpretation, the requirements translate to:

  [[#argfun-uncurry##(_F0 _x1 _x2)]] = 1 + max(x1, x2, F0(x1,x2)) > F0(x1,x2) = [[_F0(_x1, _x2)]] 

By the observations in [Kop12, Sec. 6.6], this reduction pair suffices; we may thus replace a dependency pair problem (P_0, R_1) by ({}, R_1).  By the empty set processor [Kop12, Thm. 7.15] this problem may be immediately removed.

As all dependency pair problems were succesfully simplified with sound (and complete) processors until nothing remained, we conclude termination.


+++ Citations +++

[Kop12]  C. Kop.  Higher Order Termination.  PhD Thesis, 2012.