We consider the system Applicative_05__Ex9Maps. Alphabet: cons : [d * e] --> e g : [] --> b map!fac62201 : [d -> d * e] --> e map!fac62202 : [d -> a -> d * a * e] --> e map!fac62203 : [b -> d -> c -> d * b * c * e] --> e Rules: map!fac62201(f, cons(x, y)) => cons(f x, map!fac62201(f, y)) map!fac62202(f, x, cons(y, z)) => cons(f y x, map!fac62202(f, x, z)) map!fac62203(f, g, x, cons(y, z)) => cons(f g y x, map!fac62203(f, g, x, z)) This AFS is converted to an AFSM simply by replacing all free variables by meta-variables (with arity 0). We use the dependency pair framework as described in [Kop12, Ch. 6/7], with static dependency pairs (see [KusIsoSakBla09] and the adaptation for AFSMs and accessible arguments in [Kop13]). We thus obtain the following dependency pair problem (P_0, R_0, static, formative): Dependency Pairs P_0: 0] map!fac62201#(F, cons(X, Y)) =#> map!fac62201#(F, Y) 1] map!fac62202#(F, X, cons(Y, Z)) =#> map!fac62202#(F, X, Z) 2] map!fac62203#(F, g, X, cons(Y, Z)) =#> map!fac62203#(F, g, X, Z) Rules R_0: map!fac62201(F, cons(X, Y)) => cons(F X, map!fac62201(F, Y)) map!fac62202(F, X, cons(Y, Z)) => cons(F Y X, map!fac62202(F, X, Z)) map!fac62203(F, g, X, cons(Y, Z)) => cons(F g Y X, map!fac62203(F, g, X, Z)) Thus, the original system is terminating if (P_0, R_0, static, formative) is finite. We consider the dependency pair problem (P_0, R_0, static, formative). We apply the subterm criterion with the following projection function: nu(map!fac62201#) = 2 nu(map!fac62202#) = 1 nu(map!fac62203#) = 1 Thus, we can orient the dependency pairs as follows: nu(map!fac62201#(F, cons(X, Y))) = cons(X, Y) |> Y = nu(map!fac62201#(F, Y)) nu(map!fac62202#(F, X, cons(Y, Z))) = F = F = nu(map!fac62202#(F, X, Z)) nu(map!fac62203#(F, g, X, cons(Y, Z))) = F = F = nu(map!fac62203#(F, g, X, Z)) By [Kop12, Thm. 7.35] and [Kop13, Thm. 5], we may replace a dependency pair problem (P_0, R_0, static, f) by (P_1, R_0, static, f), where P_1 contains: map!fac62202#(F, X, cons(Y, Z)) =#> map!fac62202#(F, X, Z) map!fac62203#(F, g, X, cons(Y, Z)) =#> map!fac62203#(F, g, X, Z) Thus, the original system is terminating if (P_1, R_0, static, formative) is finite. We consider the dependency pair problem (P_1, R_0, static, formative). We apply the subterm criterion with the following projection function: nu(map!fac62202#) = 3 nu(map!fac62203#) = 1 Thus, we can orient the dependency pairs as follows: nu(map!fac62202#(F, X, cons(Y, Z))) = cons(Y, Z) |> Z = nu(map!fac62202#(F, X, Z)) nu(map!fac62203#(F, g, X, cons(Y, Z))) = F = F = nu(map!fac62203#(F, g, X, Z)) By [Kop12, Thm. 7.35] and [Kop13, Thm. 5], we may replace a dependency pair problem (P_1, R_0, static, f) by (P_2, R_0, static, f), where P_2 contains: map!fac62203#(F, g, X, cons(Y, Z)) =#> map!fac62203#(F, g, X, Z) Thus, the original system is terminating if (P_2, R_0, static, formative) is finite. We consider the dependency pair problem (P_2, R_0, static, formative). We apply the subterm criterion with the following projection function: nu(map!fac62203#) = 4 Thus, we can orient the dependency pairs as follows: nu(map!fac62203#(F, g, X, cons(Y, Z))) = cons(Y, Z) |> Z = nu(map!fac62203#(F, g, X, Z)) By [Kop12, Thm. 7.35] and [Kop13, Thm. 5], we may replace a dependency pair problem (P_2, R_0, static, f) by ({}, R_0, static, f). By the empty set processor [Kop12, Thm. 7.15] this problem may be immediately removed. As all dependency pair problems were succesfully simplified with sound (and complete) processors until nothing remained, we conclude termination. +++ Citations +++ [Kop12] C. Kop. Higher Order Termination. PhD Thesis, 2012. [Kop13] C. Kop. Static Dependency Pairs with Accessibility. Unpublished manuscript, http://cl-informatik.uibk.ac.at/users/kop/static.pdf, 2013. [KusIsoSakBla09] K. Kusakari, Y. Isogai, M. Sakai, and F. Blanqui. Static Dependency Pair Method Based On Strong Computability for Higher-Order Rewrite Systems. In volume 92(10) of IEICE Transactions on Information and Systems. 2007--2015, 2009.