We consider the system sort. Alphabet: 0 : [] --> nat ascending!6220sort : [list] --> list cons : [nat * list] --> list descending!6220sort : [list] --> list insert : [nat * list * nat -> nat -> nat * nat -> nat -> nat] --> list max : [nat * nat] --> nat min : [nat * nat] --> nat nil : [] --> list s : [nat] --> nat sort : [list * nat -> nat -> nat * nat -> nat -> nat] --> list Rules: max(0, x) => x max(x, 0) => x max(s(x), s(y)) => s(max(x, y)) min(0, x) => 0 min(x, 0) => 0 min(s(x), s(y)) => s(min(x, y)) insert(x, nil, f, g) => cons(x, nil) insert(x, cons(y, z), f, g) => cons(f x y, insert(g x y, z, f, g)) sort(nil, f, g) => nil sort(cons(x, y), f, g) => insert(x, sort(y, f, g), f, g) ascending!6220sort(x) => sort(x, /\y./\z.min(y, z), /\u./\v.max(u, v)) descending!6220sort(x) => sort(x, /\y./\z.max(y, z), /\u./\v.min(u, v)) This AFS is converted to an AFSM simply by replacing all free variables by meta-variables (with arity 0). We use the dependency pair framework as described in [Kop12, Ch. 6/7], with static dependency pairs (see [KusIsoSakBla09] and the adaptation for AFSMs and accessible arguments in [Kop13]). We thus obtain the following dependency pair problem (P_0, R_0, static, formative): Dependency Pairs P_0: 0] max#(s(X), s(Y)) =#> max#(X, Y) 1] min#(s(X), s(Y)) =#> min#(X, Y) 2] insert#(X, cons(Y, Z), F, G) =#> insert#(G X Y, Z, F, G) 3] sort#(cons(X, Y), F, G) =#> insert#(X, sort(Y, F, G), F, G) 4] sort#(cons(X, Y), F, G) =#> sort#(Y, F, G) 5] ascending!6220sort#(X) =#> sort#(X, /\x./\y.min(x, y), /\z./\u.max(z, u)) 6] ascending!6220sort#(X) =#> min#(Y, Z) 7] ascending!6220sort#(X) =#> max#(Y, Z) 8] descending!6220sort#(X) =#> sort#(X, /\x./\y.max(x, y), /\z./\u.min(z, u)) 9] descending!6220sort#(X) =#> max#(Y, Z) 10] descending!6220sort#(X) =#> min#(Y, Z) Rules R_0: max(0, X) => X max(X, 0) => X max(s(X), s(Y)) => s(max(X, Y)) min(0, X) => 0 min(X, 0) => 0 min(s(X), s(Y)) => s(min(X, Y)) insert(X, nil, F, G) => cons(X, nil) insert(X, cons(Y, Z), F, G) => cons(F X Y, insert(G X Y, Z, F, G)) sort(nil, F, G) => nil sort(cons(X, Y), F, G) => insert(X, sort(Y, F, G), F, G) ascending!6220sort(X) => sort(X, /\x./\y.min(x, y), /\z./\u.max(z, u)) descending!6220sort(X) => sort(X, /\x./\y.max(x, y), /\z./\u.min(z, u)) Thus, the original system is terminating if (P_0, R_0, static, formative) is finite. We consider the dependency pair problem (P_0, R_0, static, formative). We place the elements of P in a dependency graph approximation G (see e.g. [Kop12, Thm. 7.27, 7.29], as follows: * 0 : 0 * 1 : 1 * 2 : 2 * 3 : 2 * 4 : 3, 4 * 5 : 3, 4 * 6 : 1 * 7 : 0 * 8 : 3, 4 * 9 : 0 * 10 : 1 This graph has the following strongly connected components: P_1: max#(s(X), s(Y)) =#> max#(X, Y) P_2: min#(s(X), s(Y)) =#> min#(X, Y) P_3: insert#(X, cons(Y, Z), F, G) =#> insert#(G X Y, Z, F, G) P_4: sort#(cons(X, Y), F, G) =#> sort#(Y, F, G) By [Kop12, Thm. 7.31], we may replace any dependency pair problem (P_0, R_0, m, f) by (P_1, R_0, m, f), (P_2, R_0, m, f), (P_3, R_0, m, f) and (P_4, R_0, m, f). Thus, the original system is terminating if each of (P_1, R_0, static, formative), (P_2, R_0, static, formative), (P_3, R_0, static, formative) and (P_4, R_0, static, formative) is finite. We consider the dependency pair problem (P_4, R_0, static, formative). We apply the subterm criterion with the following projection function: nu(sort#) = 1 Thus, we can orient the dependency pairs as follows: nu(sort#(cons(X, Y), F, G)) = cons(X, Y) |> Y = nu(sort#(Y, F, G)) By [Kop12, Thm. 7.35] and [Kop13, Thm. 5], we may replace a dependency pair problem (P_4, R_0, static, f) by ({}, R_0, static, f). By the empty set processor [Kop12, Thm. 7.15] this problem may be immediately removed. Thus, the original system is terminating if each of (P_1, R_0, static, formative), (P_2, R_0, static, formative) and (P_3, R_0, static, formative) is finite. We consider the dependency pair problem (P_3, R_0, static, formative). We apply the subterm criterion with the following projection function: nu(insert#) = 2 Thus, we can orient the dependency pairs as follows: nu(insert#(X, cons(Y, Z), F, G)) = cons(Y, Z) |> Z = nu(insert#(G X Y, Z, F, G)) By [Kop12, Thm. 7.35] and [Kop13, Thm. 5], we may replace a dependency pair problem (P_3, R_0, static, f) by ({}, R_0, static, f). By the empty set processor [Kop12, Thm. 7.15] this problem may be immediately removed. Thus, the original system is terminating if each of (P_1, R_0, static, formative) and (P_2, R_0, static, formative) is finite. We consider the dependency pair problem (P_2, R_0, static, formative). We apply the subterm criterion with the following projection function: nu(min#) = 1 Thus, we can orient the dependency pairs as follows: nu(min#(s(X), s(Y))) = s(X) |> X = nu(min#(X, Y)) By [Kop12, Thm. 7.35] and [Kop13, Thm. 5], we may replace a dependency pair problem (P_2, R_0, static, f) by ({}, R_0, static, f). By the empty set processor [Kop12, Thm. 7.15] this problem may be immediately removed. Thus, the original system is terminating if (P_1, R_0, static, formative) is finite. We consider the dependency pair problem (P_1, R_0, static, formative). We apply the subterm criterion with the following projection function: nu(max#) = 1 Thus, we can orient the dependency pairs as follows: nu(max#(s(X), s(Y))) = s(X) |> X = nu(max#(X, Y)) By [Kop12, Thm. 7.35] and [Kop13, Thm. 5], we may replace a dependency pair problem (P_1, R_0, static, f) by ({}, R_0, static, f). By the empty set processor [Kop12, Thm. 7.15] this problem may be immediately removed. As all dependency pair problems were succesfully simplified with sound (and complete) processors until nothing remained, we conclude termination. +++ Citations +++ [Kop12] C. Kop. Higher Order Termination. PhD Thesis, 2012. [Kop13] C. Kop. Static Dependency Pairs with Accessibility. Unpublished manuscript, http://cl-informatik.uibk.ac.at/users/kop/static.pdf, 2013. [KusIsoSakBla09] K. Kusakari, Y. Isogai, M. Sakai, and F. Blanqui. Static Dependency Pair Method Based On Strong Computability for Higher-Order Rewrite Systems. In volume 92(10) of IEICE Transactions on Information and Systems. 2007--2015, 2009.