We consider the system AotoYamada_05__009. Alphabet: and : [c * c] --> c cons : [a * b] --> b false : [] --> c forall : [a -> c * b] --> c forsome : [a -> c * b] --> c nil : [] --> b or : [c * c] --> c true : [] --> c Rules: and(true, true) => true and(true, false) => false and(false, true) => false and(false, false) => false or(true, true) => true or(true, false) => true or(false, true) => true or(false, false) => false forall(f, nil) => true forall(f, cons(x, y)) => and(f x, forall(f, y)) forsome(f, nil) => false forsome(f, cons(x, y)) => or(f x, forsome(f, y)) This AFS is converted to an AFSM simply by replacing all free variables by meta-variables (with arity 0). We use the dependency pair framework as described in [Kop12, Ch. 6/7], with static dependency pairs (see [KusIsoSakBla09] and the adaptation for AFSMs and accessible arguments in [Kop13]). We thus obtain the following dependency pair problem (P_0, R_0, static, formative): Dependency Pairs P_0: 0] forall#(F, cons(X, Y)) =#> and#(F X, forall(F, Y)) 1] forall#(F, cons(X, Y)) =#> forall#(F, Y) 2] forsome#(F, cons(X, Y)) =#> or#(F X, forsome(F, Y)) 3] forsome#(F, cons(X, Y)) =#> forsome#(F, Y) Rules R_0: and(true, true) => true and(true, false) => false and(false, true) => false and(false, false) => false or(true, true) => true or(true, false) => true or(false, true) => true or(false, false) => false forall(F, nil) => true forall(F, cons(X, Y)) => and(F X, forall(F, Y)) forsome(F, nil) => false forsome(F, cons(X, Y)) => or(F X, forsome(F, Y)) Thus, the original system is terminating if (P_0, R_0, static, formative) is finite. We consider the dependency pair problem (P_0, R_0, static, formative). We place the elements of P in a dependency graph approximation G (see e.g. [Kop12, Thm. 7.27, 7.29], as follows: * 0 : * 1 : 0, 1 * 2 : * 3 : 2, 3 This graph has the following strongly connected components: P_1: forall#(F, cons(X, Y)) =#> forall#(F, Y) P_2: forsome#(F, cons(X, Y)) =#> forsome#(F, Y) By [Kop12, Thm. 7.31], we may replace any dependency pair problem (P_0, R_0, m, f) by (P_1, R_0, m, f) and (P_2, R_0, m, f). Thus, the original system is terminating if each of (P_1, R_0, static, formative) and (P_2, R_0, static, formative) is finite. We consider the dependency pair problem (P_2, R_0, static, formative). We apply the subterm criterion with the following projection function: nu(forsome#) = 2 Thus, we can orient the dependency pairs as follows: nu(forsome#(F, cons(X, Y))) = cons(X, Y) |> Y = nu(forsome#(F, Y)) By [Kop12, Thm. 7.35] and [Kop13, Thm. 5], we may replace a dependency pair problem (P_2, R_0, static, f) by ({}, R_0, static, f). By the empty set processor [Kop12, Thm. 7.15] this problem may be immediately removed. Thus, the original system is terminating if (P_1, R_0, static, formative) is finite. We consider the dependency pair problem (P_1, R_0, static, formative). We apply the subterm criterion with the following projection function: nu(forall#) = 2 Thus, we can orient the dependency pairs as follows: nu(forall#(F, cons(X, Y))) = cons(X, Y) |> Y = nu(forall#(F, Y)) By [Kop12, Thm. 7.35] and [Kop13, Thm. 5], we may replace a dependency pair problem (P_1, R_0, static, f) by ({}, R_0, static, f). By the empty set processor [Kop12, Thm. 7.15] this problem may be immediately removed. As all dependency pair problems were succesfully simplified with sound (and complete) processors until nothing remained, we conclude termination. +++ Citations +++ [Kop12] C. Kop. Higher Order Termination. PhD Thesis, 2012. [Kop13] C. Kop. Static Dependency Pairs with Accessibility. Unpublished manuscript, http://cl-informatik.uibk.ac.at/users/kop/static.pdf, 2013. [KusIsoSakBla09] K. Kusakari, Y. Isogai, M. Sakai, and F. Blanqui. Static Dependency Pair Method Based On Strong Computability for Higher-Order Rewrite Systems. In volume 92(10) of IEICE Transactions on Information and Systems. 2007--2015, 2009.