We consider the system 445. Alphabet: f : [(A -> A) -> A] --> A Rules: f(/\g.X(g)) => X(/\x.x) We use the dependency pair framework as described in [Kop12, Ch. 6/7], with dynamic dependency pairs. We thus obtain the following dependency pair problem (P_0, R_0, minimal, formative): Dependency Pairs P_0: 0] f#(/\g.X(g)) =#> X(/\x.x) Rules R_0: f(/\g.X(g)) => X(/\x.x) Thus, the original system is terminating if (P_0, R_0, minimal, formative) is finite. We consider the dependency pair problem (P_0, R_0, minimal, formative). This combination (P_0, R_0) has no formative rules! We will name the empty set of rules:R_1. By [Kop12, Thm. 7.17], we may replace the dependency pair problem (P_0, R_0, minimal, formative) by (P_0, R_1, minimal, formative). Thus, the original system is terminating if (P_0, R_1, minimal, formative) is finite. We consider the dependency pair problem (P_0, R_1, minimal, formative). We will use the reduction pair processor [Kop12, Thm. 7.16]. As the system is abstraction-simple and the formative flag is set, it suffices to find a tagged reduction pair [Kop12, Def. 6.70]. Thus, we must orient: f#(/\g.X(g)) >? X(/\x.x) We apply [Kop12, Thm. 6.75] and use the following argument functions: pi( f#(F) ) = #argfun-f##(F (/\x.x)) We orient these requirements with a polynomial interpretation in the natural numbers. The following interpretation satisfies the requirements: #argfun-f## = \y0.1 + y0 f# = \G0.0 Using this interpretation, the requirements translate to: [[#argfun-f##((/\g._x0(g)) (/\x.x))]] = 1 + F0(\y0.y0) > F0(\y0.y0) = [[_x0(/\x.x)]] By the observations in [Kop12, Sec. 6.6], this reduction pair suffices; we may thus replace a dependency pair problem (P_0, R_1) by ({}, R_1). By the empty set processor [Kop12, Thm. 7.15] this problem may be immediately removed. As all dependency pair problems were succesfully simplified with sound (and complete) processors until nothing remained, we conclude termination. +++ Citations +++ [Kop12] C. Kop. Higher Order Termination. PhD Thesis, 2012.