We consider the system 482. Alphabet: apply : [o -> o * o] --> o compo : [o -> o * o -> o * o] --> o Rules: compo(/\x.X(x), /\y.Y(y), Z) => X(Y(Z)) apply(/\x.X(x), Y) => X(Y) We use the dependency pair framework as described in [Kop12, Ch. 6/7], with dynamic dependency pairs. We thus obtain the following dependency pair problem (P_0, R_0, minimal, formative): Dependency Pairs P_0: 0] compo#(/\x.X(x), /\y.Y(y), Z) =#> X(Y(Z)) 1] compo#(/\x.X(x), /\y.Y(y), Z) =#> Y(Z) {X : 1} 2] apply#(/\x.X(x), Y) =#> X(Y) Rules R_0: compo(/\x.X(x), /\y.Y(y), Z) => X(Y(Z)) apply(/\x.X(x), Y) => X(Y) Thus, the original system is terminating if (P_0, R_0, minimal, formative) is finite. We consider the dependency pair problem (P_0, R_0, minimal, formative). This combination (P_0, R_0) has no formative rules! We will name the empty set of rules:R_1. By [Kop12, Thm. 7.17], we may replace the dependency pair problem (P_0, R_0, minimal, formative) by (P_0, R_1, minimal, formative). Thus, the original system is terminating if (P_0, R_1, minimal, formative) is finite. We consider the dependency pair problem (P_0, R_1, minimal, formative). We will use the reduction pair processor [Kop12, Thm. 7.16]. As the system is abstraction-simple and the formative flag is set, it suffices to find a tagged reduction pair [Kop12, Def. 6.70]. Thus, we must orient: compo#(/\x.X(x), /\y.Y(y), Z) >? X(Y(Z)) compo#(/\x.X(x), /\y.Y(y), Z) >? Y(Z) apply#(/\x.X(x), Y) >? X(Y) We apply [Kop12, Thm. 6.75] and use the following argument functions: pi( apply#(F, X) ) = #argfun-apply##(F X) pi( compo#(F, G, X) ) = #argfun-compo##(F (G X), G X) We orient these requirements with a polynomial interpretation in the natural numbers. The following interpretation satisfies the requirements: #argfun-apply## = \y0.3 + y0 #argfun-compo## = \y0y1.3 + max(y0, y1) apply# = \G0y1.0 compo# = \G0G1y2.0 Using this interpretation, the requirements translate to: [[#argfun-compo##((/\x._x0(x)) ((/\y._x1(y)) _x2), (/\z._x1(z)) _x2)]] = 3 + max(x2, F0(max(x2, F1(x2))), F1(x2)) > F0(F1(x2)) = [[_x0(_x1(_x2))]] [[#argfun-compo##((/\x._x0(x)) ((/\y._x1(y)) _x2), (/\z._x1(z)) _x2)]] = 3 + max(x2, F0(max(x2, F1(x2))), F1(x2)) > F1(x2) = [[_x1(_x2)]] [[#argfun-apply##((/\x._x0(x)) _x1)]] = 3 + max(x1, F0(x1)) > F0(x1) = [[_x0(_x1)]] By the observations in [Kop12, Sec. 6.6], this reduction pair suffices; we may thus replace a dependency pair problem (P_0, R_1) by ({}, R_1). By the empty set processor [Kop12, Thm. 7.15] this problem may be immediately removed. As all dependency pair problems were succesfully simplified with sound (and complete) processors until nothing remained, we conclude termination. +++ Citations +++ [Kop12] C. Kop. Higher Order Termination. PhD Thesis, 2012.