We consider the system 459. Alphabet: and : [form * form] --> form exists : [term -> form] --> form forall : [term -> form] --> form neg : [form] --> form or : [form * form] --> form Rules: neg(neg(X)) => X neg(and(X, Y)) => or(neg(X), neg(Y)) neg(or(X, Y)) => and(neg(X), neg(Y)) neg(forall(/\x.X(x))) => exists(/\y.neg(X(y))) neg(exists(/\x.X(x))) => forall(/\y.neg(X(y))) We use rule removal, following [Kop12, Theorem 2.23]. This gives the following requirements (possibly using Theorems 2.25 and 2.26 in [Kop12]): neg(neg(X)) >? X neg(and(X, Y)) >? or(neg(X), neg(Y)) neg(or(X, Y)) >? and(neg(X), neg(Y)) neg(forall(/\x.X(x))) >? exists(/\y.neg(X(y))) neg(exists(/\x.X(x))) >? forall(/\y.neg(X(y))) We orient these requirements with a polynomial interpretation in the natural numbers. The following interpretation satisfies the requirements: and = \y0y1.y0 + y1 exists = \G0.1 + 2G0(0) forall = \G0.2 + 2G0(0) neg = \y0.2y0 or = \y0y1.y0 + y1 Using this interpretation, the requirements translate to: [[neg(neg(_x0))]] = 4x0 >= x0 = [[_x0]] [[neg(and(_x0, _x1))]] = 2x0 + 2x1 >= 2x0 + 2x1 = [[or(neg(_x0), neg(_x1))]] [[neg(or(_x0, _x1))]] = 2x0 + 2x1 >= 2x0 + 2x1 = [[and(neg(_x0), neg(_x1))]] [[neg(forall(/\x._x0(x)))]] = 4 + 4F0(0) > 1 + 4F0(0) = [[exists(/\x.neg(_x0(x)))]] [[neg(exists(/\x._x0(x)))]] = 2 + 4F0(0) >= 2 + 4F0(0) = [[forall(/\x.neg(_x0(x)))]] We can thus remove the following rules: neg(forall(/\x.X(x))) => exists(/\y.neg(X(y))) We use rule removal, following [Kop12, Theorem 2.23]. This gives the following requirements (possibly using Theorems 2.25 and 2.26 in [Kop12]): neg(neg(X)) >? X neg(and(X, Y)) >? or(neg(X), neg(Y)) neg(or(X, Y)) >? and(neg(X), neg(Y)) neg(exists(/\x.X(x))) >? forall(/\y.neg(X(y))) We orient these requirements with a polynomial interpretation in the natural numbers. The following interpretation satisfies the requirements: and = \y0y1.y0 + y1 exists = \G0.3 + 3G0(0) forall = \G0.G0(0) neg = \y0.y0 or = \y0y1.y0 + y1 Using this interpretation, the requirements translate to: [[neg(neg(_x0))]] = x0 >= x0 = [[_x0]] [[neg(and(_x0, _x1))]] = x0 + x1 >= x0 + x1 = [[or(neg(_x0), neg(_x1))]] [[neg(or(_x0, _x1))]] = x0 + x1 >= x0 + x1 = [[and(neg(_x0), neg(_x1))]] [[neg(exists(/\x._x0(x)))]] = 3 + 3F0(0) > F0(0) = [[forall(/\x.neg(_x0(x)))]] We can thus remove the following rules: neg(exists(/\x.X(x))) => forall(/\y.neg(X(y))) We use rule removal, following [Kop12, Theorem 2.23]. This gives the following requirements (possibly using Theorems 2.25 and 2.26 in [Kop12]): neg(neg(X)) >? X neg(and(X, Y)) >? or(neg(X), neg(Y)) neg(or(X, Y)) >? and(neg(X), neg(Y)) We orient these requirements with a polynomial interpretation in the natural numbers. The following interpretation satisfies the requirements: and = \y0y1.3 + y0 + y1 neg = \y0.3y0 or = \y0y1.3 + y0 + y1 Using this interpretation, the requirements translate to: [[neg(neg(_x0))]] = 9x0 >= x0 = [[_x0]] [[neg(and(_x0, _x1))]] = 9 + 3x0 + 3x1 > 3 + 3x0 + 3x1 = [[or(neg(_x0), neg(_x1))]] [[neg(or(_x0, _x1))]] = 9 + 3x0 + 3x1 > 3 + 3x0 + 3x1 = [[and(neg(_x0), neg(_x1))]] We can thus remove the following rules: neg(and(X, Y)) => or(neg(X), neg(Y)) neg(or(X, Y)) => and(neg(X), neg(Y)) We use rule removal, following [Kop12, Theorem 2.23]. This gives the following requirements (possibly using Theorems 2.25 and 2.26 in [Kop12]): neg(neg(X)) >? X We orient these requirements with a polynomial interpretation in the natural numbers. The following interpretation satisfies the requirements: neg = \y0.3 + y0 Using this interpretation, the requirements translate to: [[neg(neg(_x0))]] = 6 + x0 > x0 = [[_x0]] We can thus remove the following rules: neg(neg(X)) => X All rules were succesfully removed. Thus, termination of the original system has been reduced to termination of the beta-rule, which is well-known to hold. +++ Citations +++ [Kop12] C. Kop. Higher Order Termination. PhD Thesis, 2012.