We consider the system h56. Alphabet: cons : [a * b] --> b foldr : [a -> b -> b * b * b] --> b nil : [] --> b xap : [a -> b -> b * a] --> b -> b yap : [b -> b * b] --> b Rules: foldr(/\x./\y.yap(xap(f, x), y), z, nil) => z foldr(/\x./\y.yap(xap(f, x), y), z, cons(u, v)) => yap(xap(f, u), foldr(/\w./\x'.yap(xap(f, w), x'), z, v)) xap(f, x) => f x yap(f, x) => f x This AFS is converted to an AFSM simply by replacing all free variables by meta-variables (with arity 0). Symbol xap is an encoding for application that is only used in innocuous ways. We can simplify the program (without losing non-termination) by removing it. This gives: Alphabet: cons : [a * b] --> b foldr : [a -> b -> b * b * b] --> b nil : [] --> b yap : [b -> b * b] --> b Rules: foldr(/\x./\y.yap(F(x), y), X, nil) => X foldr(/\x./\y.yap(F(x), y), X, cons(Y, Z)) => yap(F(Y), foldr(/\z./\u.yap(F(z), u), X, Z)) yap(F, X) => F X We use rule removal, following [Kop12, Theorem 2.23]. This gives the following requirements (possibly using Theorems 2.25 and 2.26 in [Kop12]): foldr(/\x./\y.yap(F(x), y), X, nil) >? X foldr(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >? yap(F(Y), foldr(/\z./\u.yap(F(z), u), X, Z)) yap(F, X) >? F X We use a recursive path ordering as defined in [Kop12, Chapter 5]. We choose Lex = {} and Mul = {@_{o -> o}, cons, foldr, nil, yap}, and the following precedence: cons > nil > foldr > yap > @_{o -> o} With these choices, we have: 1] foldr(/\x./\y.yap(F(x), y), X, nil) > X because [2], by definition 2] foldr*(/\x./\y.yap(F(x), y), X, nil) >= X because [3], by (Select) 3] X >= X by (Meta) 4] foldr(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >= yap(F(Y), foldr(/\x./\y.yap(F(x), y), X, Z)) because [5], by (Star) 5] foldr*(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >= yap(F(Y), foldr(/\x./\y.yap(F(x), y), X, Z)) because foldr > yap, [6] and [13], by (Copy) 6] foldr*(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >= F(Y) because [7], by (Select) 7] /\x.yap(F(foldr*(/\y./\z.yap(F(y), z), X, cons(Y, Z))), x) >= F(Y) because [8], by (Eta)[Kop13:2] 8] F(foldr*(/\x./\y.yap(F(x), y), X, cons(Y, Z))) >= F(Y) because [9], by (Meta) 9] foldr*(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >= Y because [10], by (Select) 10] cons(Y, Z) >= Y because [11], by (Star) 11] cons*(Y, Z) >= Y because [12], by (Select) 12] Y >= Y by (Meta) 13] foldr*(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >= foldr(/\x./\y.yap(F(x), y), X, Z) because foldr in Mul, [14], [20] and [21], by (Stat) 14] /\x./\z.yap(F(x), z) >= /\x./\z.yap(F(x), z) because [15], by (Abs) 15] /\z.yap(F(y), z) >= /\z.yap(F(y), z) because [16], by (Abs) 16] yap(F(y), x) >= yap(F(y), x) because yap in Mul, [17] and [19], by (Fun) 17] F(y) >= F(y) because [18], by (Meta) 18] y >= y by (Var) 19] x >= x by (Var) 20] X >= X by (Meta) 21] cons(Y, Z) > Z because [22], by definition 22] cons*(Y, Z) >= Z because [23], by (Select) 23] Z >= Z by (Meta) 24] yap(F, X) >= @_{o -> o}(F, X) because [25], by (Star) 25] yap*(F, X) >= @_{o -> o}(F, X) because yap > @_{o -> o}, [26] and [28], by (Copy) 26] yap*(F, X) >= F because [27], by (Select) 27] F >= F by (Meta) 28] yap*(F, X) >= X because [29], by (Select) 29] X >= X by (Meta) We can thus remove the following rules: foldr(/\x./\y.yap(F(x), y), X, nil) => X We use rule removal, following [Kop12, Theorem 2.23]. This gives the following requirements (possibly using Theorems 2.25 and 2.26 in [Kop12]): foldr(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >? yap(F(Y), foldr(/\z./\u.yap(F(z), u), X, Z)) yap(F, X) >? F X We use a recursive path ordering as defined in [Kop12, Chapter 5]. We choose Lex = {} and Mul = {@_{o -> o}, cons, foldr, yap}, and the following precedence: cons > foldr > yap > @_{o -> o} With these choices, we have: 1] foldr(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >= yap(F(Y), foldr(/\x./\y.yap(F(x), y), X, Z)) because [2], by (Star) 2] foldr*(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >= yap(F(Y), foldr(/\x./\y.yap(F(x), y), X, Z)) because foldr > yap, [3] and [10], by (Copy) 3] foldr*(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >= F(Y) because [4], by (Select) 4] /\x.yap(F(foldr*(/\y./\z.yap(F(y), z), X, cons(Y, Z))), x) >= F(Y) because [5], by (Eta)[Kop13:2] 5] F(foldr*(/\x./\y.yap(F(x), y), X, cons(Y, Z))) >= F(Y) because [6], by (Meta) 6] foldr*(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >= Y because [7], by (Select) 7] cons(Y, Z) >= Y because [8], by (Star) 8] cons*(Y, Z) >= Y because [9], by (Select) 9] Y >= Y by (Meta) 10] foldr*(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >= foldr(/\x./\y.yap(F(x), y), X, Z) because foldr in Mul, [11], [17] and [18], by (Stat) 11] /\x./\z.yap(F(x), z) >= /\x./\z.yap(F(x), z) because [12], by (Abs) 12] /\z.yap(F(y), z) >= /\z.yap(F(y), z) because [13], by (Abs) 13] yap(F(y), x) >= yap(F(y), x) because yap in Mul, [14] and [16], by (Fun) 14] F(y) >= F(y) because [15], by (Meta) 15] y >= y by (Var) 16] x >= x by (Var) 17] X >= X by (Meta) 18] cons(Y, Z) > Z because [19], by definition 19] cons*(Y, Z) >= Z because [20], by (Select) 20] Z >= Z by (Meta) 21] yap(F, X) > @_{o -> o}(F, X) because [22], by definition 22] yap*(F, X) >= @_{o -> o}(F, X) because yap > @_{o -> o}, [23] and [25], by (Copy) 23] yap*(F, X) >= F because [24], by (Select) 24] F >= F by (Meta) 25] yap*(F, X) >= X because [26], by (Select) 26] X >= X by (Meta) We can thus remove the following rules: yap(F, X) => F X We use rule removal, following [Kop12, Theorem 2.23]. This gives the following requirements (possibly using Theorems 2.25 and 2.26 in [Kop12]): foldr(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >? yap(F(Y), foldr(/\z./\u.yap(F(z), u), X, Z)) We use a recursive path ordering as defined in [Kop12, Chapter 5]. We choose Lex = {} and Mul = {cons, foldr, yap}, and the following precedence: yap > foldr > cons With these choices, we have: 1] foldr(/\x./\y.yap(F(x), y), X, cons(Y, Z)) > yap(F(Y), foldr(/\x./\y.yap(F(x), y), X, Z)) because [2], by definition 2] foldr*(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >= yap(F(Y), foldr(/\x./\y.yap(F(x), y), X, Z)) because [3], by (Select) 3] yap(F(foldr*(/\x./\y.yap(F(x), y), X, cons(Y, Z))), foldr*(/\z./\u.yap(F(z), u), X, cons(Y, Z))) >= yap(F(Y), foldr(/\x./\y.yap(F(x), y), X, Z)) because yap in Mul, [4] and [9], by (Fun) 4] F(foldr*(/\x./\y.yap(F(x), y), X, cons(Y, Z))) >= F(Y) because [5], by (Meta) 5] foldr*(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >= Y because [6], by (Select) 6] cons(Y, Z) >= Y because [7], by (Star) 7] cons*(Y, Z) >= Y because [8], by (Select) 8] Y >= Y by (Meta) 9] foldr*(/\x./\y.yap(F(x), y), X, cons(Y, Z)) >= foldr(/\x./\y.yap(F(x), y), X, Z) because foldr in Mul, [10], [16] and [17], by (Stat) 10] /\x./\z.yap(F(x), z) >= /\x./\z.yap(F(x), z) because [11], by (Abs) 11] /\z.yap(F(y), z) >= /\z.yap(F(y), z) because [12], by (Abs) 12] yap(F(y), x) >= yap(F(y), x) because yap in Mul, [13] and [15], by (Fun) 13] F(y) >= F(y) because [14], by (Meta) 14] y >= y by (Var) 15] x >= x by (Var) 16] X >= X by (Meta) 17] cons(Y, Z) > Z because [18], by definition 18] cons*(Y, Z) >= Z because [19], by (Select) 19] Z >= Z by (Meta) We can thus remove the following rules: foldr(/\x./\y.yap(F(x), y), X, cons(Y, Z)) => yap(F(Y), foldr(/\z./\u.yap(F(z), u), X, Z)) All rules were succesfully removed. Thus, termination of the original system has been reduced to termination of the beta-rule, which is well-known to hold. +++ Citations +++ [Kop12] C. Kop. Higher Order Termination. PhD Thesis, 2012. [Kop13:2] C. Kop. StarHorpo with an Eta-Rule. Unpublished manuscript, http://cl-informatik.uibk.ac.at/users/kop/etahorpo.pdf, 2013.