We consider the system h57. Alphabet: 0 : [] --> nat cons : [] --> nat -> list -> list foldr : [] --> (nat -> nat -> nat) -> nat -> list -> nat length : [] --> list -> nat nil : [] --> list s : [] --> nat -> nat Rules: foldr (/\x./\y.f x y) z nil => z foldr (/\x./\y.f x y) z (cons u v) => f u (foldr (/\w./\x'.f w x') z v) length x => foldr (/\y./\z.s z) 0 x Using the transformations described in [Kop11], this system can be brought in a form without leading free variables in the left-hand side, and where the left-hand side of a variable is always a functional term or application headed by a functional term. We now transform the resulting AFS into an AFSM by replacing all free variables by meta-variables (with arity 0). This leads to the following AFSM: Alphabet: 0 : [] --> nat cons : [nat * list] --> list foldr : [nat -> nat -> nat * nat * list] --> nat length : [list] --> nat nil : [] --> list s : [nat] --> nat ~AP1 : [nat -> nat -> nat * nat] --> nat -> nat Rules: foldr(/\x./\y.~AP1(F, x) y, X, nil) => X foldr(/\x./\y.~AP1(F, x) y, X, cons(Y, Z)) => ~AP1(F, Y) foldr(/\z./\u.~AP1(F, z) u, X, Z) length(X) => foldr(/\x./\y.s(y), 0, X) ~AP1(F, X) => F X Symbol ~AP1 is an encoding for application that is only used in innocuous ways. We can simplify the program (without losing non-termination) by removing it. This gives: Alphabet: 0 : [] --> nat cons : [nat * list] --> list foldr : [nat -> nat -> nat * nat * list] --> nat length : [list] --> nat nil : [] --> list s : [nat] --> nat Rules: foldr(/\x./\y.X(x, y), Y, nil) => Y foldr(/\x./\y.X(x, y), Y, cons(Z, U)) => X(Z, foldr(/\z./\u.X(z, u), Y, U)) length(X) => foldr(/\x./\y.s(y), 0, X) We use rule removal, following [Kop12, Theorem 2.23]. This gives the following requirements (possibly using Theorems 2.25 and 2.26 in [Kop12]): foldr(/\x./\y.X(x, y), Y, nil) >? Y foldr(/\x./\y.X(x, y), Y, cons(Z, U)) >? X(Z, foldr(/\z./\u.X(z, u), Y, U)) length(X) >? foldr(/\x./\y.s(y), 0, X) We use a recursive path ordering as defined in [Kop12, Chapter 5]. Argument functions: [[0]] = _|_ [[s(x_1)]] = x_1 We choose Lex = {} and Mul = {cons, foldr, length, nil}, and the following precedence: cons > length > nil > foldr Taking the argument function into account, and fixing the greater / greater equal choices, the constraints can be denoted as follows: foldr(/\x./\y.X(x, y), Y, nil) >= Y foldr(/\x./\y.X(x, y), Y, cons(Z, U)) > X(Z, foldr(/\x./\y.X(x, y), Y, U)) length(X) > foldr(/\x./\y.y, _|_, X) With these choices, we have: 1] foldr(/\x./\y.X(x, y), Y, nil) >= Y because [2], by (Star) 2] foldr*(/\x./\y.X(x, y), Y, nil) >= Y because [3], by (Select) 3] Y >= Y by (Meta) 4] foldr(/\x./\y.X(x, y), Y, cons(Z, U)) > X(Z, foldr(/\x./\y.X(x, y), Y, U)) because [5], by definition 5] foldr*(/\x./\y.X(x, y), Y, cons(Z, U)) >= X(Z, foldr(/\x./\y.X(x, y), Y, U)) because [6], by (Select) 6] X(foldr*(/\x./\y.X(x, y), Y, cons(Z, U)), foldr*(/\z./\u.X(z, u), Y, cons(Z, U))) >= X(Z, foldr(/\x./\y.X(x, y), Y, U)) because [7] and [11], by (Meta) 7] foldr*(/\x./\y.X(x, y), Y, cons(Z, U)) >= Z because [8], by (Select) 8] cons(Z, U) >= Z because [9], by (Star) 9] cons*(Z, U) >= Z because [10], by (Select) 10] Z >= Z by (Meta) 11] foldr*(/\x./\y.X(x, y), Y, cons(Z, U)) >= foldr(/\x./\y.X(x, y), Y, U) because foldr in Mul, [12], [17] and [18], by (Stat) 12] /\x./\z.X(x, z) >= /\x./\z.X(x, z) because [13], by (Abs) 13] /\z.X(y, z) >= /\z.X(y, z) because [14], by (Abs) 14] X(y, x) >= X(y, x) because [15] and [16], by (Meta) 15] y >= y by (Var) 16] x >= x by (Var) 17] Y >= Y by (Meta) 18] cons(Z, U) > U because [19], by definition 19] cons*(Z, U) >= U because [20], by (Select) 20] U >= U by (Meta) 21] length(X) > foldr(/\x./\y.y, _|_, X) because [22], by definition 22] length*(X) >= foldr(/\x./\y.y, _|_, X) because length > foldr, [23], [27] and [28], by (Copy) 23] length*(X) >= /\y./\z.z because [24], by (F-Abs) 24] length*(X, x) >= /\z.z because [25], by (F-Abs) 25] length*(X, x, y) >= y because [26], by (Select) 26] y >= y by (Var) 27] length*(X) >= _|_ by (Bot) 28] length*(X) >= X because [29], by (Select) 29] X >= X by (Meta) We can thus remove the following rules: foldr(/\x./\y.X(x, y), Y, cons(Z, U)) => X(Z, foldr(/\z./\u.X(z, u), Y, U)) length(X) => foldr(/\x./\y.s(y), 0, X) We use rule removal, following [Kop12, Theorem 2.23]. This gives the following requirements (possibly using Theorems 2.25 and 2.26 in [Kop12]): foldr(/\x./\y.X(x, y), Y, nil) >? Y We use a recursive path ordering as defined in [Kop12, Chapter 5]. We choose Lex = {} and Mul = {foldr, nil}, and the following precedence: nil > foldr With these choices, we have: 1] foldr(/\x./\y.X(x, y), Y, nil) > Y because [2], by definition 2] foldr*(/\x./\y.X(x, y), Y, nil) >= Y because [3], by (Select) 3] Y >= Y by (Meta) We can thus remove the following rules: foldr(/\x./\y.X(x, y), Y, nil) => Y All rules were succesfully removed. Thus, termination of the original system has been reduced to termination of the beta-rule, which is well-known to hold. +++ Citations +++ [Kop11] C. Kop. Simplifying Algebraic Functional Systems. In Proceedings of CAI 2011, volume 6742 of LNCS. 201--215, Springer, 2011. [Kop12] C. Kop. Higher Order Termination. PhD Thesis, 2012.