We consider the system h55. Alphabet: cons : [] --> a -> b -> b foldr : [] --> (a -> b -> b) -> b -> b -> b nil : [] --> b Rules: foldr (/\x./\y.f x y) z nil => z foldr (/\x./\y.f x y) z (cons u v) => f u (foldr (/\w./\x'.f w x') z v) Using the transformations described in [Kop11], this system can be brought in a form without leading free variables in the left-hand side, and where the left-hand side of a variable is always a functional term or application headed by a functional term. We now transform the resulting AFS into an AFSM by replacing all free variables by meta-variables (with arity 0). This leads to the following AFSM: Alphabet: cons : [a * b] --> b foldr : [a -> b -> b * b * b] --> b nil : [] --> b ~AP1 : [a -> b -> b * a] --> b -> b Rules: foldr(/\x./\y.~AP1(F, x) y, X, nil) => X foldr(/\x./\y.~AP1(F, x) y, X, cons(Y, Z)) => ~AP1(F, Y) foldr(/\z./\u.~AP1(F, z) u, X, Z) foldr(/\x./\y.cons(x, y), X, nil) => X foldr(/\x./\y.cons(x, y), X, cons(Y, Z)) => cons(Y, foldr(/\z./\u.cons(z, u), X, Z)) ~AP1(F, X) => F X Symbol ~AP1 is an encoding for application that is only used in innocuous ways. We can simplify the program (without losing non-termination) by removing it. Additionally, we can remove some (now-)redundant rules. This gives: Alphabet: cons : [a * b] --> b foldr : [a -> b -> b * b * b] --> b nil : [] --> b Rules: foldr(/\x./\y.X(x, y), Y, nil) => Y foldr(/\x./\y.X(x, y), Y, cons(Z, U)) => X(Z, foldr(/\z./\u.X(z, u), Y, U)) We use the dependency pair framework as described in [Kop12, Ch. 6/7], with static dependency pairs (see [KusIsoSakBla09] and the adaptation for AFSMs and accessible arguments in [FuhKop19]). We thus obtain the following dependency pair problem (P_0, R_0, computable, formative): Dependency Pairs P_0: 0] foldr#(/\x./\y.X(x, y), Y, cons(Z, U)) =#> foldr#(/\z./\u.X(z, u), Y, U) {X : 2} Rules R_0: foldr(/\x./\y.X(x, y), Y, nil) => Y foldr(/\x./\y.X(x, y), Y, cons(Z, U)) => X(Z, foldr(/\z./\u.X(z, u), Y, U)) Thus, the original system is terminating if (P_0, R_0, computable, formative) is finite. We consider the dependency pair problem (P_0, R_0, computable, formative). We apply the subterm criterion with the following projection function: nu(foldr#) = 3 Thus, we can orient the dependency pairs as follows: nu(foldr#(/\x./\y.X(x, y), Y, cons(Z, U))) = cons(Z, U) |> U = nu(foldr#(/\z./\u.X(z, u), Y, U)) By [FuhKop19, Thm. 61], we may replace a dependency pair problem (P_0, R_0, computable, f) by ({}, R_0, computable, f). By the empty set processor [Kop12, Thm. 7.15] this problem may be immediately removed. As all dependency pair problems were succesfully simplified with sound (and complete) processors until nothing remained, we conclude termination. +++ Citations +++ [FuhKop19] C. Fuhs, and C. Kop. A static higher-order dependency pair framework. In Proceedings of ESOP 2019, 2019. [Kop11] C. Kop. Simplifying Algebraic Functional Systems. In Proceedings of CAI 2011, volume 6742 of LNCS. 201--215, Springer, 2011. [Kop12] C. Kop. Higher Order Termination. PhD Thesis, 2012. [KusIsoSakBla09] K. Kusakari, Y. Isogai, M. Sakai, and F. Blanqui. Static Dependency Pair Method Based On Strong Computability for Higher-Order Rewrite Systems. In volume 92(10) of IEICE Transactions on Information and Systems. 2007--2015, 2009.