We consider the system Applicative_first_order_05__31. Alphabet: !faccolon : [] --> b -> b -> b !facplus : [] --> b -> b -> b a : [] --> b cons : [] --> d -> e -> e false : [] --> c filter : [] --> (d -> c) -> e -> e filter2 : [] --> c -> (d -> c) -> d -> e -> e g : [] --> b -> a -> b map : [] --> (d -> d) -> e -> e nil : [] --> e true : [] --> c Rules: !faccolon (!faccolon x y) z => !faccolon x (!faccolon y z) !faccolon (!facplus x y) z => !facplus (!faccolon x z) (!faccolon y z) !faccolon x (!facplus y (f z)) => !faccolon (g x z) (!facplus y a) map f nil => nil map f (cons x y) => cons (f x) (map f y) filter f nil => nil filter f (cons x y) => filter2 (f x) f x y filter2 true f x y => cons x (filter f y) filter2 false f x y => filter f y Using the transformations described in [Kop11], this system can be brought in a form without leading free variables in the left-hand side, and where the left-hand side of a variable is always a functional term or application headed by a functional term. We now transform the resulting AFS into an AFSM by replacing all free variables by meta-variables (with arity 0). This leads to the following AFSM: Alphabet: !faccolon : [b * b] --> b !facplus : [b * b] --> b a : [] --> b cons : [d * e] --> e false : [] --> c filter : [d -> c * e] --> e filter2 : [c * d -> c * d * e] --> e g : [b] --> a -> b map : [d -> d * e] --> e nil : [] --> e true : [] --> c ~AP1 : [a -> b * a] --> b Rules: !faccolon(!faccolon(X, Y), Z) => !faccolon(X, !faccolon(Y, Z)) !faccolon(!facplus(X, Y), Z) => !facplus(!faccolon(X, Z), !faccolon(Y, Z)) !faccolon(X, !facplus(Y, ~AP1(F, Z))) => !faccolon(~AP1(g(X), Z), !facplus(Y, a)) map(F, nil) => nil map(F, cons(X, Y)) => cons(F X, map(F, Y)) filter(F, nil) => nil filter(F, cons(X, Y)) => filter2(F X, F, X, Y) filter2(true, F, X, Y) => cons(X, filter(F, Y)) filter2(false, F, X, Y) => filter(F, Y) ~AP1(F, X) => F X We use the dependency pair framework as described in [Kop12, Ch. 6/7], with static dependency pairs (see [KusIsoSakBla09] and the adaptation for AFSMs and accessible arguments in [FuhKop19]). In order to do so, we start by eta-expanding the system, which gives: !faccolon(!faccolon(X, Y), Z) => !faccolon(X, !faccolon(Y, Z)) !faccolon(!facplus(X, Y), Z) => !facplus(!faccolon(X, Z), !faccolon(Y, Z)) !faccolon(X, !facplus(Y, ~AP1(F, Z))) => !faccolon(~AP1(/\x.g(X, x), Z), !facplus(Y, a)) map(F, nil) => nil map(F, cons(X, Y)) => cons(F X, map(F, Y)) filter(F, nil) => nil filter(F, cons(X, Y)) => filter2(F X, F, X, Y) filter2(true, F, X, Y) => cons(X, filter(F, Y)) filter2(false, F, X, Y) => filter(F, Y) ~AP1(F, X) => F X We thus obtain the following dependency pair problem (P_0, R_0, computable, formative): Dependency Pairs P_0: 0] !faccolon#(!faccolon(X, Y), Z) =#> !faccolon#(X, !faccolon(Y, Z)) 1] !faccolon#(!faccolon(X, Y), Z) =#> !faccolon#(Y, Z) 2] !faccolon#(!facplus(X, Y), Z) =#> !faccolon#(X, Z) 3] !faccolon#(!facplus(X, Y), Z) =#> !faccolon#(Y, Z) 4] !faccolon#(X, !facplus(Y, ~AP1(F, Z))) =#> !faccolon#(~AP1(/\x.g(X, x), Z), !facplus(Y, a)) 5] !faccolon#(X, !facplus(Y, ~AP1(F, Z))) =#> ~AP1#(/\x.g(X, x), Z) 6] map#(F, cons(X, Y)) =#> map#(F, Y) 7] filter#(F, cons(X, Y)) =#> filter2#(F X, F, X, Y) 8] filter2#(true, F, X, Y) =#> filter#(F, Y) 9] filter2#(false, F, X, Y) =#> filter#(F, Y) Rules R_0: !faccolon(!faccolon(X, Y), Z) => !faccolon(X, !faccolon(Y, Z)) !faccolon(!facplus(X, Y), Z) => !facplus(!faccolon(X, Z), !faccolon(Y, Z)) !faccolon(X, !facplus(Y, ~AP1(F, Z))) => !faccolon(~AP1(/\x.g(X, x), Z), !facplus(Y, a)) map(F, nil) => nil map(F, cons(X, Y)) => cons(F X, map(F, Y)) filter(F, nil) => nil filter(F, cons(X, Y)) => filter2(F X, F, X, Y) filter2(true, F, X, Y) => cons(X, filter(F, Y)) filter2(false, F, X, Y) => filter(F, Y) ~AP1(F, X) => F X Thus, the original system is terminating if (P_0, R_0, computable, formative) is finite. We consider the dependency pair problem (P_0, R_0, computable, formative). We place the elements of P in a dependency graph approximation G (see e.g. [Kop12, Thm. 7.27, 7.29], as follows: * 0 : 0, 1, 2, 3, 4, 5 * 1 : 0, 1, 2, 3, 4, 5 * 2 : 0, 1, 2, 3, 4, 5 * 3 : 0, 1, 2, 3, 4, 5 * 4 : 0, 1, 2, 3 * 5 : * 6 : 6 * 7 : 8, 9 * 8 : 7 * 9 : 7 This graph has the following strongly connected components: P_1: !faccolon#(!faccolon(X, Y), Z) =#> !faccolon#(X, !faccolon(Y, Z)) !faccolon#(!faccolon(X, Y), Z) =#> !faccolon#(Y, Z) !faccolon#(!facplus(X, Y), Z) =#> !faccolon#(X, Z) !faccolon#(!facplus(X, Y), Z) =#> !faccolon#(Y, Z) !faccolon#(X, !facplus(Y, ~AP1(F, Z))) =#> !faccolon#(~AP1(/\x.g(X, x), Z), !facplus(Y, a)) P_2: map#(F, cons(X, Y)) =#> map#(F, Y) P_3: filter#(F, cons(X, Y)) =#> filter2#(F X, F, X, Y) filter2#(true, F, X, Y) =#> filter#(F, Y) filter2#(false, F, X, Y) =#> filter#(F, Y) By [Kop12, Thm. 7.31], we may replace any dependency pair problem (P_0, R_0, m, f) by (P_1, R_0, m, f), (P_2, R_0, m, f) and (P_3, R_0, m, f). Thus, the original system is terminating if each of (P_1, R_0, computable, formative), (P_2, R_0, computable, formative) and (P_3, R_0, computable, formative) is finite. We consider the dependency pair problem (P_3, R_0, computable, formative). We apply the subterm criterion with the following projection function: nu(filter2#) = 4 nu(filter#) = 2 Thus, we can orient the dependency pairs as follows: nu(filter#(F, cons(X, Y))) = cons(X, Y) |> Y = nu(filter2#(F X, F, X, Y)) nu(filter2#(true, F, X, Y)) = Y = Y = nu(filter#(F, Y)) nu(filter2#(false, F, X, Y)) = Y = Y = nu(filter#(F, Y)) By [FuhKop19, Thm. 61], we may replace a dependency pair problem (P_3, R_0, computable, f) by (P_4, R_0, computable, f), where P_4 contains: filter2#(true, F, X, Y) =#> filter#(F, Y) filter2#(false, F, X, Y) =#> filter#(F, Y) Thus, the original system is terminating if each of (P_1, R_0, computable, formative), (P_2, R_0, computable, formative) and (P_4, R_0, computable, formative) is finite. We consider the dependency pair problem (P_4, R_0, computable, formative). We place the elements of P in a dependency graph approximation G (see e.g. [Kop12, Thm. 7.27, 7.29], as follows: * 0 : * 1 : This graph has no strongly connected components. By [Kop12, Thm. 7.31], this implies finiteness of the dependency pair problem. Thus, the original system is terminating if each of (P_1, R_0, computable, formative) and (P_2, R_0, computable, formative) is finite. We consider the dependency pair problem (P_2, R_0, computable, formative). We apply the subterm criterion with the following projection function: nu(map#) = 2 Thus, we can orient the dependency pairs as follows: nu(map#(F, cons(X, Y))) = cons(X, Y) |> Y = nu(map#(F, Y)) By [FuhKop19, Thm. 61], we may replace a dependency pair problem (P_2, R_0, computable, f) by ({}, R_0, computable, f). By the empty set processor [Kop12, Thm. 7.15] this problem may be immediately removed. Thus, the original system is terminating if (P_1, R_0, computable, formative) is finite. We consider the dependency pair problem (P_1, R_0, computable, formative). The formative rules of (P_1, R_0) are R_1 ::= !faccolon(!faccolon(X, Y), Z) => !faccolon(X, !faccolon(Y, Z)) !faccolon(!facplus(X, Y), Z) => !facplus(!faccolon(X, Z), !faccolon(Y, Z)) !faccolon(X, !facplus(Y, ~AP1(F, Z))) => !faccolon(~AP1(/\x.g(X, x), Z), !facplus(Y, a)) ~AP1(F, X) => F X By [Kop12, Thm. 7.17], we may replace the dependency pair problem (P_1, R_0, computable, formative) by (P_1, R_1, computable, formative). Thus, the original system is terminating if (P_1, R_1, computable, formative) is finite. We consider the dependency pair problem (P_1, R_1, computable, formative). We will use the reduction pair processor [Kop12, Thm. 7.16]. It suffices to find a standard reduction pair [Kop12, Def. 6.69]. Thus, we must orient: !faccolon#(!faccolon(X, Y), Z) >? !faccolon#(X, !faccolon(Y, Z)) !faccolon#(!faccolon(X, Y), Z) >? !faccolon#(Y, Z) !faccolon#(!facplus(X, Y), Z) >? !faccolon#(X, Z) !faccolon#(!facplus(X, Y), Z) >? !faccolon#(Y, Z) !faccolon#(X, !facplus(Y, ~AP1(F, Z))) >? !faccolon#(~AP1(/\x.g(X, x), Z), !facplus(Y, a)) !faccolon(!faccolon(X, Y), Z) >= !faccolon(X, !faccolon(Y, Z)) !faccolon(!facplus(X, Y), Z) >= !facplus(!faccolon(X, Z), !faccolon(Y, Z)) !faccolon(X, !facplus(Y, ~AP1(F, Z))) >= !faccolon(~AP1(/\x.g(X, x), Z), !facplus(Y, a)) ~AP1(F, X) >= F X We orient these requirements with a polynomial interpretation in the natural numbers. The following interpretation satisfies the requirements: !faccolon = \y0y1.0 !faccolon# = \y0y1.2y1 !facplus = \y0y1.y1 a = 0 g = \y0y1.0 ~AP1 = \G0y1.2 + G0(y1) Using this interpretation, the requirements translate to: [[!faccolon#(!faccolon(_x0, _x1), _x2)]] = 2x2 >= 0 = [[!faccolon#(_x0, !faccolon(_x1, _x2))]] [[!faccolon#(!faccolon(_x0, _x1), _x2)]] = 2x2 >= 2x2 = [[!faccolon#(_x1, _x2)]] [[!faccolon#(!facplus(_x0, _x1), _x2)]] = 2x2 >= 2x2 = [[!faccolon#(_x0, _x2)]] [[!faccolon#(!facplus(_x0, _x1), _x2)]] = 2x2 >= 2x2 = [[!faccolon#(_x1, _x2)]] [[!faccolon#(_x0, !facplus(_x1, ~AP1(_F2, _x3)))]] = 4 + 2F2(x3) > 0 = [[!faccolon#(~AP1(/\x.g(_x0, x), _x3), !facplus(_x1, a))]] [[!faccolon(!faccolon(_x0, _x1), _x2)]] = 0 >= 0 = [[!faccolon(_x0, !faccolon(_x1, _x2))]] [[!faccolon(!facplus(_x0, _x1), _x2)]] = 0 >= 0 = [[!facplus(!faccolon(_x0, _x2), !faccolon(_x1, _x2))]] [[!faccolon(_x0, !facplus(_x1, ~AP1(_F2, _x3)))]] = 0 >= 0 = [[!faccolon(~AP1(/\x.g(_x0, x), _x3), !facplus(_x1, a))]] [[~AP1(_F0, _x1)]] = 2 + F0(x1) >= F0(x1) = [[_F0 _x1]] By the observations in [Kop12, Sec. 6.6], this reduction pair suffices; we may thus replace the dependency pair problem (P_1, R_1, computable, formative) by (P_5, R_1, computable, formative), where P_5 consists of: !faccolon#(!faccolon(X, Y), Z) =#> !faccolon#(X, !faccolon(Y, Z)) !faccolon#(!faccolon(X, Y), Z) =#> !faccolon#(Y, Z) !faccolon#(!facplus(X, Y), Z) =#> !faccolon#(X, Z) !faccolon#(!facplus(X, Y), Z) =#> !faccolon#(Y, Z) Thus, the original system is terminating if (P_5, R_1, computable, formative) is finite. We consider the dependency pair problem (P_5, R_1, computable, formative). We apply the subterm criterion with the following projection function: nu(!faccolon#) = 1 Thus, we can orient the dependency pairs as follows: nu(!faccolon#(!faccolon(X, Y), Z)) = !faccolon(X, Y) |> X = nu(!faccolon#(X, !faccolon(Y, Z))) nu(!faccolon#(!faccolon(X, Y), Z)) = !faccolon(X, Y) |> Y = nu(!faccolon#(Y, Z)) nu(!faccolon#(!facplus(X, Y), Z)) = !facplus(X, Y) |> X = nu(!faccolon#(X, Z)) nu(!faccolon#(!facplus(X, Y), Z)) = !facplus(X, Y) |> Y = nu(!faccolon#(Y, Z)) By [FuhKop19, Thm. 61], we may replace a dependency pair problem (P_5, R_1, computable, f) by ({}, R_1, computable, f). By the empty set processor [Kop12, Thm. 7.15] this problem may be immediately removed. As all dependency pair problems were succesfully simplified with sound (and complete) processors until nothing remained, we conclude termination. +++ Citations +++ [FuhKop19] C. Fuhs, and C. Kop. 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