We consider the system h12. Alphabet: 0 : [] --> a rec : [] --> (a -> b -> b) -> b -> a -> b s : [] --> a -> a Rules: rec (/\x./\y.f x y) z 0 => z rec (/\x./\y.f x y) z (s u) => f (s u) (rec (/\v./\w.f v w) z u) Using the transformations described in [Kop11], this system can be brought in a form without leading free variables in the left-hand side, and where the left-hand side of a variable is always a functional term or application headed by a functional term. We now transform the resulting AFS into an AFSM by replacing all free variables by meta-variables (with arity 0). This leads to the following AFSM: Alphabet: 0 : [] --> a rec : [a -> b -> b * b * a] --> b s : [a] --> a ~AP1 : [a -> b -> b * a] --> b -> b Rules: rec(/\x./\y.~AP1(F, x) y, X, 0) => X rec(/\x./\y.~AP1(F, x) y, X, s(Y)) => ~AP1(F, s(Y)) rec(/\z./\u.~AP1(F, z) u, X, Y) ~AP1(F, X) => F X Symbol ~AP1 is an encoding for application that is only used in innocuous ways. We can simplify the program (without losing non-termination) by removing it. This gives: Alphabet: 0 : [] --> a rec : [a -> b -> b * b * a] --> b s : [a] --> a Rules: rec(/\x./\y.X(x, y), Y, 0) => Y rec(/\x./\y.X(x, y), Y, s(Z)) => X(s(Z), rec(/\z./\u.X(z, u), Y, Z)) We use the dependency pair framework as described in [Kop12, Ch. 6/7], with static dependency pairs (see [KusIsoSakBla09] and the adaptation for AFSMs and accessible arguments in [FuhKop19]). We thus obtain the following dependency pair problem (P_0, R_0, computable, formative): Dependency Pairs P_0: 0] rec#(/\x./\y.X(x, y), Y, s(Z)) =#> rec#(/\z./\u.X(z, u), Y, Z) {X : 2} Rules R_0: rec(/\x./\y.X(x, y), Y, 0) => Y rec(/\x./\y.X(x, y), Y, s(Z)) => X(s(Z), rec(/\z./\u.X(z, u), Y, Z)) Thus, the original system is terminating if (P_0, R_0, computable, formative) is finite. We consider the dependency pair problem (P_0, R_0, computable, formative). We apply the subterm criterion with the following projection function: nu(rec#) = 3 Thus, we can orient the dependency pairs as follows: nu(rec#(/\x./\y.X(x, y), Y, s(Z))) = s(Z) |> Z = nu(rec#(/\z./\u.X(z, u), Y, Z)) By [FuhKop19, Thm. 61], we may replace a dependency pair problem (P_0, R_0, computable, f) by ({}, R_0, computable, f). By the empty set processor [Kop12, Thm. 7.15] this problem may be immediately removed. As all dependency pair problems were succesfully simplified with sound (and complete) processors until nothing remained, we conclude termination. +++ Citations +++ [FuhKop19] C. Fuhs, and C. Kop. A static higher-order dependency pair framework. In Proceedings of ESOP 2019, 2019. [Kop11] C. Kop. Simplifying Algebraic Functional Systems. In Proceedings of CAI 2011, volume 6742 of LNCS. 201--215, Springer, 2011. [Kop12] C. Kop. Higher Order Termination. PhD Thesis, 2012. [KusIsoSakBla09] K. Kusakari, Y. Isogai, M. Sakai, and F. Blanqui. Static Dependency Pair Method Based On Strong Computability for Higher-Order Rewrite Systems. In volume 92(10) of IEICE Transactions on Information and Systems. 2007--2015, 2009.