We consider the system h03. Alphabet: 0 : [] --> c 1 : [] --> c add : [] --> c -> a -> c cons : [a * b] --> b fold : [c -> a -> c * b * c] --> c mul : [] --> c -> a -> c nil : [] --> b prod : [b] --> c sum : [b] --> c xap : [c -> a -> c * c] --> a -> c yap : [a -> c * a] --> c Rules: fold(/\x./\y.yap(xap(f, x), y), nil, z) => z fold(/\x./\y.yap(xap(f, x), y), cons(z, u), v) => fold(/\w./\x'.yap(xap(f, w), x'), u, yap(xap(f, v), z)) sum(x) => fold(/\y./\z.yap(xap(add, y), z), x, 0) fold(mul, x, 1) => prod(x) xap(f, x) => f x yap(f, x) => f x This AFS is converted to an AFSM simply by replacing all free variables by meta-variables (with arity 0). Symbol xap is an encoding for application that is only used in innocuous ways. We can simplify the program (without losing non-termination) by removing it. This gives: Alphabet: 0 : [] --> c 1 : [] --> c add : [c] --> a -> c cons : [a * b] --> b fold : [c -> a -> c * b * c] --> c mul : [] --> c -> a -> c nil : [] --> b prod : [b] --> c sum : [b] --> c yap : [a -> c * a] --> c Rules: fold(/\x./\y.yap(F(x), y), nil, X) => X fold(/\x./\y.yap(F(x), y), cons(X, Y), Z) => fold(/\z./\u.yap(F(z), u), Y, yap(F(Z), X)) sum(X) => fold(/\x./\y.yap(add(x), y), X, 0) fold(mul, X, 1) => prod(X) yap(F, X) => F X We use the dependency pair framework as described in [Kop12, Ch. 6/7], with dynamic dependency pairs. After applying [Kop12, Thm. 7.22] to denote collapsing dependency pairs in an extended form, we thus obtain the following dependency pair problem (P_0, R_0, minimal, all): Dependency Pairs P_0: 0] fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) =#> fold#(/\z./\u.yap(F(z), u), Y, yap(F(Z), X)) 1] fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) =#> yap#(F(z), u) 2] fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) =#> F(z) 3] fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) =#> yap#(F(Z), X) 4] fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) =#> F(Z) 5] sum#(X) =#> fold#(/\x./\y.yap(add(x), y), X, 0) 6] sum#(X) =#> yap#(add(x), y) 7] yap#(F, X) =#> F(X) Rules R_0: fold(/\x./\y.yap(F(x), y), nil, X) => X fold(/\x./\y.yap(F(x), y), cons(X, Y), Z) => fold(/\z./\u.yap(F(z), u), Y, yap(F(Z), X)) sum(X) => fold(/\x./\y.yap(add(x), y), X, 0) fold(mul, X, 1) => prod(X) yap(F, X) => F X Thus, the original system is terminating if (P_0, R_0, minimal, all) is finite. We consider the dependency pair problem (P_0, R_0, minimal, all). We place the elements of P in a dependency graph approximation G (see e.g. [Kop12, Thm. 7.27, 7.29], as follows: * 0 : 0, 1, 2, 3, 4 * 1 : * 2 : 0, 1, 2, 3, 4, 5, 6, 7 * 3 : 7 * 4 : 0, 1, 2, 3, 4, 5, 6, 7 * 5 : 0, 1, 2, 3, 4 * 6 : * 7 : 0, 1, 2, 3, 4, 5, 6, 7 This graph has the following strongly connected components: P_1: fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) =#> fold#(/\z./\u.yap(F(z), u), Y, yap(F(Z), X)) fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) =#> F(z) fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) =#> yap#(F(Z), X) fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) =#> F(Z) sum#(X) =#> fold#(/\x./\y.yap(add(x), y), X, 0) yap#(F, X) =#> F(X) By [Kop12, Thm. 7.31], we may replace any dependency pair problem (P_0, R_0, m, f) by (P_1, R_0, m, f). Thus, the original system is terminating if (P_1, R_0, minimal, all) is finite. We consider the dependency pair problem (P_1, R_0, minimal, all). We will use the reduction pair processor [Kop12, Thm. 7.16]. It suffices to find a standard reduction pair [Kop12, Def. 6.69]. Thus, we must orient: fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) >? fold#(/\z./\u.yap(F(z), u), Y, yap(F(Z), X)) fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) >? F(~c1) ~c0 fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) >? yap#(F(Z), X) fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) >? F(Z) ~c2 sum#(X) >? fold#(/\x./\y.yap(add(x), y), X, 0) yap#(F, X) >? F(X) fold(/\x./\y.yap(F(x), y), nil, X) >= X fold(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= fold(/\z./\u.yap(F(z), u), Y, yap(F(Z), X)) sum(X) >= fold(/\x./\y.yap(add(x), y), X, 0) fold(mul, X, 1) >= prod(X) yap(F, X) >= F X fold(F, X, Y) >= fold#(F, X, Y) sum(X) >= sum#(X) yap(F, X) >= yap#(F, X) We apply [Kop12, Thm. 6.75] and use the following argument functions: pi( sum#(X) ) = #argfun-sum##(fold#(/\x./\y.yap(add(x), y), X, 0)) pi( yap#(F, X) ) = #argfun-yap##(F X) Since this representation is not advantageous for the higher-order recursive path ordering, we present the strict requirements in their unextended form, which is not problematic since for any F, s and substituion gamma: (F s)gamma beta-reduces to F(s)gamma.) We use a recursive path ordering as defined in [Kop12, Chapter 5]. Argument functions: [[0]] = _|_ [[@_{o -> o}(x_1, x_2)]] = @_{o -> o}(x_2, x_1) [[fold(x_1, x_2, x_3)]] = fold(x_2, x_1, x_3) [[fold#(x_1, x_2, x_3)]] = fold#(x_2, x_1, x_3) [[prod(x_1)]] = x_1 [[sum#(x_1)]] = x_1 [[~c0]] = _|_ [[~c1]] = _|_ [[~c2]] = _|_ We choose Lex = {@_{o -> o}, fold, fold#} and Mul = {#argfun-sum##, #argfun-yap##, 1, add, cons, mul, nil, sum, yap, yap#}, and the following precedence: 1 > cons > sum > #argfun-sum## > nil > add > fold > fold# > yap > mul > #argfun-yap## > yap# > @_{o -> o} Taking the argument function into account, and fixing the greater / greater equal choices, the constraints can be denoted as follows: fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) > fold#(/\x./\y.yap(F(x), y), Y, yap(F(Z), X)) fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= @_{o -> o}(F(_|_), _|_) fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) > #argfun-yap##(@_{o -> o}(F(Z), X)) fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) > @_{o -> o}(F(Z), _|_) #argfun-sum##(fold#(/\x./\y.yap(add(x), y), X, _|_)) > fold#(/\x./\y.yap(add(x), y), X, _|_) #argfun-yap##(@_{o -> o}(F, X)) >= @_{o -> o}(F, X) fold(/\x./\y.yap(F(x), y), nil, X) >= X fold(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= fold(/\x./\y.yap(F(x), y), Y, yap(F(Z), X)) sum(X) >= fold(/\x./\y.yap(add(x), y), X, _|_) fold(mul, X, 1) >= X yap(F, X) >= @_{o -> o}(F, X) fold(F, X, Y) >= fold#(F, X, Y) sum(X) >= #argfun-sum##(fold#(/\x./\y.yap(add(x), y), X, _|_)) yap(F, X) >= #argfun-yap##(@_{o -> o}(F, X)) With these choices, we have: 1] fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) > fold#(/\x./\y.yap(F(x), y), Y, yap(F(Z), X)) because [2], by definition 2] fold#*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= fold#(/\x./\y.yap(F(x), y), Y, yap(F(Z), X)) because [3], [6], [13] and [15], by (Stat) 3] cons(X, Y) > Y because [4], by definition 4] cons*(X, Y) >= Y because [5], by (Select) 5] Y >= Y by (Meta) 6] fold#*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= /\x./\y.yap(F(x), y) because [7], by (Select) 7] /\x./\z.yap(F(x), z) >= /\x./\z.yap(F(x), z) because [8], by (Abs) 8] /\z.yap(F(y), z) >= /\z.yap(F(y), z) because [9], by (Abs) 9] yap(F(y), x) >= yap(F(y), x) because yap in Mul, [10] and [12], by (Fun) 10] F(y) >= F(y) because [11], by (Meta) 11] y >= y by (Var) 12] x >= x by (Var) 13] fold#*(/\z./\u.yap(F(z), u), cons(X, Y), Z) >= Y because [14], by (Select) 14] cons(X, Y) >= Y because [4], by (Star) 15] fold#*(/\z./\u.yap(F(z), u), cons(X, Y), Z) >= yap(F(Z), X) because fold# > yap, [16] and [21], by (Copy) 16] fold#*(/\z./\u.yap(F(z), u), cons(X, Y), Z) >= F(Z) because [17], by (Select) 17] /\z.yap(F(fold#*(/\u./\v.yap(F(u), v), cons(X, Y), Z)), z) >= F(Z) because [18], by (Eta)[Kop13:2] 18] F(fold#*(/\z./\u.yap(F(z), u), cons(X, Y), Z)) >= F(Z) because [19], by (Meta) 19] fold#*(/\z./\u.yap(F(z), u), cons(X, Y), Z) >= Z because [20], by (Select) 20] Z >= Z by (Meta) 21] fold#*(/\z./\u.yap(F(z), u), cons(X, Y), Z) >= X because [22], by (Select) 22] cons(X, Y) >= X because [23], by (Star) 23] cons*(X, Y) >= X because [24], by (Select) 24] X >= X by (Meta) 25] fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= @_{o -> o}(F(_|_), _|_) because [26], by (Star) 26] fold#*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= @_{o -> o}(F(_|_), _|_) because fold# > @_{o -> o}, [27] and [31], by (Copy) 27] fold#*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= F(_|_) because [28], by (Select) 28] /\x.yap(F(fold#*(/\y./\z.yap(F(y), z), cons(X, Y), Z)), x) >= F(_|_) because [29], by (Eta)[Kop13:2] 29] F(fold#*(/\x./\y.yap(F(x), y), cons(X, Y), Z)) >= F(_|_) because [30], by (Meta) 30] fold#*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= _|_ by (Bot) 31] fold#*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= _|_ by (Bot) 32] fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) > #argfun-yap##(@_{o -> o}(F(Z), X)) because [33], by definition 33] fold#*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= #argfun-yap##(@_{o -> o}(F(Z), X)) because fold# > #argfun-yap## and [34], by (Copy) 34] fold#*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= @_{o -> o}(F(Z), X) because fold# > @_{o -> o}, [16] and [21], by (Copy) 35] fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) > @_{o -> o}(F(Z), _|_) because [36], by definition 36] fold#*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= @_{o -> o}(F(Z), _|_) because [37], by (Select) 37] yap(F(fold#*(/\x./\y.yap(F(x), y), cons(X, Y), Z)), fold#*(/\z./\u.yap(F(z), u), cons(X, Y), Z)) >= @_{o -> o}(F(Z), _|_) because [38], by (Star) 38] yap*(F(fold#*(/\x./\y.yap(F(x), y), cons(X, Y), Z)), fold#*(/\z./\u.yap(F(z), u), cons(X, Y), Z)) >= @_{o -> o}(F(Z), _|_) because yap > @_{o -> o}, [39] and [40], by (Copy) 39] yap*(F(fold#*(/\x./\y.yap(F(x), y), cons(X, Y), Z)), fold#*(/\z./\u.yap(F(z), u), cons(X, Y), Z)) >= F(Z) because [18], by (Select) 40] yap*(F(fold#*(/\x./\y.yap(F(x), y), cons(X, Y), Z)), fold#*(/\z./\u.yap(F(z), u), cons(X, Y), Z)) >= _|_ by (Bot) 41] #argfun-sum##(fold#(/\x./\y.yap(add(x), y), X, _|_)) > fold#(/\x./\y.yap(add(x), y), X, _|_) because [42], by definition 42] #argfun-sum##*(fold#(/\x./\y.yap(add(x), y), X, _|_)) >= fold#(/\x./\y.yap(add(x), y), X, _|_) because [43], by (Select) 43] fold#(/\x./\y.yap(add(x), y), X, _|_) >= fold#(/\x./\y.yap(add(x), y), X, _|_) because [44], [50] and [51], by (Fun) 44] /\x./\z.yap(add(x), z) >= /\x./\z.yap(add(x), z) because [45], by (Abs) 45] /\z.yap(add(y), z) >= /\z.yap(add(y), z) because [46], by (Abs) 46] yap(add(y), x) >= yap(add(y), x) because yap in Mul, [47] and [49], by (Fun) 47] add(y) >= add(y) because add in Mul and [48], by (Fun) 48] y >= y by (Var) 49] x >= x by (Var) 50] X >= X by (Meta) 51] _|_ >= _|_ by (Bot) 52] #argfun-yap##(@_{o -> o}(F, X)) >= @_{o -> o}(F, X) because [53], by (Star) 53] #argfun-yap##*(@_{o -> o}(F, X)) >= @_{o -> o}(F, X) because [54], by (Select) 54] @_{o -> o}(F, X) >= @_{o -> o}(F, X) because [55] and [56], by (Fun) 55] F >= F by (Meta) 56] X >= X by (Meta) 57] fold(/\x./\y.yap(F(x), y), nil, X) >= X because [58], by (Star) 58] fold*(/\x./\y.yap(F(x), y), nil, X) >= X because [59], by (Select) 59] X >= X by (Meta) 60] fold(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= fold(/\x./\y.yap(F(x), y), Y, yap(F(Z), X)) because [61], by (Star) 61] fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= fold(/\x./\y.yap(F(x), y), Y, yap(F(Z), X)) because [3], [62], [63] and [64], by (Stat) 62] fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= /\x./\y.yap(F(x), y) because [7], by (Select) 63] fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= Y because [14], by (Select) 64] fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= yap(F(Z), X) because fold > yap, [65] and [69], by (Copy) 65] fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= F(Z) because [66], by (Select) 66] /\x.yap(F(fold*(/\y./\z.yap(F(y), z), cons(X, Y), Z)), x) >= F(Z) because [67], by (Eta)[Kop13:2] 67] F(fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z)) >= F(Z) because [68], by (Meta) 68] fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= Z because [20], by (Select) 69] fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= X because [70], by (Select) 70] yap(F(fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z)), fold*(/\z./\u.yap(F(z), u), cons(X, Y), Z)) >= X because [71], by (Star) 71] yap*(F(fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z)), fold*(/\z./\u.yap(F(z), u), cons(X, Y), Z)) >= X because [72], by (Select) 72] fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= X because [73], by (Select) 73] cons(X, Y) >= X because [23], by (Star) 74] sum(X) >= fold(/\x./\y.yap(add(x), y), X, _|_) because [75], by (Star) 75] sum*(X) >= fold(/\x./\y.yap(add(x), y), X, _|_) because sum > fold, [76], [84] and [85], by (Copy) 76] sum*(X) >= /\y./\z.yap(add(y), z) because [77], by (F-Abs) 77] sum*(X, x) >= /\z.yap(add(x), z) because [78], by (F-Abs) 78] sum*(X, x, y) >= yap(add(x), y) because sum > yap, [79] and [82], by (Copy) 79] sum*(X, x, y) >= add(x) because sum > add and [80], by (Copy) 80] sum*(X, x, y) >= x because [81], by (Select) 81] x >= x by (Var) 82] sum*(X, x, y) >= y because [83], by (Select) 83] y >= y by (Var) 84] sum*(X) >= X because [50], by (Select) 85] sum*(X) >= _|_ by (Bot) 86] fold(mul, X, 1) >= X because [87], by (Star) 87] fold*(mul, X, 1) >= X because [88], by (Select) 88] X >= X by (Meta) 89] yap(F, X) >= @_{o -> o}(F, X) because [90], by (Star) 90] yap*(F, X) >= @_{o -> o}(F, X) because yap > @_{o -> o}, [91] and [92], by (Copy) 91] yap*(F, X) >= F because [55], by (Select) 92] yap*(F, X) >= X because [56], by (Select) 93] fold(F, X, Y) >= fold#(F, X, Y) because [94], by (Star) 94] fold*(F, X, Y) >= fold#(F, X, Y) because fold > fold#, [95], [97] and [99], by (Copy) 95] fold*(F, X, Y) >= F because [96], by (Select) 96] F >= F by (Meta) 97] fold*(F, X, Y) >= X because [98], by (Select) 98] X >= X by (Meta) 99] fold*(F, X, Y) >= Y because [100], by (Select) 100] Y >= Y by (Meta) 101] sum(X) >= #argfun-sum##(fold#(/\x./\y.yap(add(x), y), X, _|_)) because [102], by (Star) 102] sum*(X) >= #argfun-sum##(fold#(/\x./\y.yap(add(x), y), X, _|_)) because sum > #argfun-sum## and [103], by (Copy) 103] sum*(X) >= fold#(/\x./\y.yap(add(x), y), X, _|_) because sum > fold#, [104], [112] and [114], by (Copy) 104] sum*(X) >= /\y./\z.yap(add(y), z) because [105], by (F-Abs) 105] sum*(X, x) >= /\z.yap(add(x), z) because [106], by (F-Abs) 106] sum*(X, x, y) >= yap(add(x), y) because sum > yap, [107] and [110], by (Copy) 107] sum*(X, x, y) >= add(x) because sum > add and [108], by (Copy) 108] sum*(X, x, y) >= x because [109], by (Select) 109] x >= x by (Var) 110] sum*(X, x, y) >= y because [111], by (Select) 111] y >= y by (Var) 112] sum*(X) >= X because [113], by (Select) 113] X >= X by (Meta) 114] sum*(X) >= _|_ by (Bot) 115] yap(F, X) >= #argfun-yap##(@_{o -> o}(F, X)) because [116], by (Star) 116] yap*(F, X) >= #argfun-yap##(@_{o -> o}(F, X)) because yap > #argfun-yap## and [117], by (Copy) 117] yap*(F, X) >= @_{o -> o}(F, X) because yap > @_{o -> o}, [118] and [120], by (Copy) 118] yap*(F, X) >= F because [119], by (Select) 119] F >= F by (Meta) 120] yap*(F, X) >= X because [121], by (Select) 121] X >= X by (Meta) By the observations in [Kop12, Sec. 6.6], this reduction pair suffices; we may thus replace the dependency pair problem (P_1, R_0, minimal, all) by (P_2, R_0, minimal, all), where P_2 consists of: fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) =#> F(z) yap#(F, X) =#> F(X) Thus, the original system is terminating if (P_2, R_0, minimal, all) is finite. We consider the dependency pair problem (P_2, R_0, minimal, all). We will use the reduction pair processor [Kop12, Thm. 7.16]. It suffices to find a standard reduction pair [Kop12, Def. 6.69]. Thus, we must orient: fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) >? F(~c1) ~c0 yap#(F, X) >? F(X) fold(/\x./\y.yap(F(x), y), nil, X) >= X fold(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= fold(/\z./\u.yap(F(z), u), Y, yap(F(Z), X)) sum(X) >= fold(/\x./\y.yap(add(x), y), X, 0) fold(mul, X, 1) >= prod(X) yap(F, X) >= F X fold(F, X, Y) >= fold#(F, X, Y) yap(F, X) >= yap#(F, X) We apply [Kop12, Thm. 6.75] and use the following argument functions: pi( yap#(F, X) ) = #argfun-yap##(F X) Since this representation is not advantageous for the higher-order recursive path ordering, we present the strict requirements in their unextended form, which is not problematic since for any F, s and substituion gamma: (F s)gamma beta-reduces to F(s)gamma.) We use a recursive path ordering as defined in [Kop12, Chapter 5]. Argument functions: [[0]] = _|_ [[fold(x_1, x_2, x_3)]] = fold(x_2, x_1, x_3) [[prod(x_1)]] = x_1 [[~c0]] = _|_ [[~c1]] = _|_ We choose Lex = {fold} and Mul = {#argfun-yap##, 1, @_{o -> o}, add, cons, fold#, mul, nil, sum, yap, yap#}, and the following precedence: 1 > mul > nil > sum > add > yap# > fold > yap > #argfun-yap## > fold# > @_{o -> o} > cons Taking the argument function into account, and fixing the greater / greater equal choices, the constraints can be denoted as follows: fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) > @_{o -> o}(F(_|_), _|_) #argfun-yap##(@_{o -> o}(F, X)) >= @_{o -> o}(F, X) fold(/\x./\y.yap(F(x), y), nil, X) >= X fold(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= fold(/\x./\y.yap(F(x), y), Y, yap(F(Z), X)) sum(X) >= fold(/\x./\y.yap(add(x), y), X, _|_) fold(mul, X, 1) >= X yap(F, X) >= @_{o -> o}(F, X) fold(F, X, Y) >= fold#(F, X, Y) yap(F, X) >= #argfun-yap##(@_{o -> o}(F, X)) With these choices, we have: 1] fold#(/\x./\y.yap(F(x), y), cons(X, Y), Z) > @_{o -> o}(F(_|_), _|_) because [2], by definition 2] fold#*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= @_{o -> o}(F(_|_), _|_) because fold# > @_{o -> o}, [3] and [7], by (Copy) 3] fold#*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= F(_|_) because [4], by (Select) 4] /\x.yap(F(fold#*(/\y./\z.yap(F(y), z), cons(X, Y), Z)), x) >= F(_|_) because [5], by (Eta)[Kop13:2] 5] F(fold#*(/\x./\y.yap(F(x), y), cons(X, Y), Z)) >= F(_|_) because [6], by (Meta) 6] fold#*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= _|_ by (Bot) 7] fold#*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= _|_ by (Bot) 8] #argfun-yap##(@_{o -> o}(F, X)) >= @_{o -> o}(F, X) because [9], by (Star) 9] #argfun-yap##*(@_{o -> o}(F, X)) >= @_{o -> o}(F, X) because [10], by (Select) 10] @_{o -> o}(F, X) >= @_{o -> o}(F, X) because @_{o -> o} in Mul, [11] and [12], by (Fun) 11] F >= F by (Meta) 12] X >= X by (Meta) 13] fold(/\x./\y.yap(F(x), y), nil, X) >= X because [14], by (Star) 14] fold*(/\x./\y.yap(F(x), y), nil, X) >= X because [15], by (Select) 15] X >= X by (Meta) 16] fold(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= fold(/\x./\y.yap(F(x), y), Y, yap(F(Z), X)) because [17], by (Star) 17] fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= fold(/\x./\y.yap(F(x), y), Y, yap(F(Z), X)) because [18], [21], [31] and [33], by (Stat) 18] cons(X, Y) > Y because [19], by definition 19] cons*(X, Y) >= Y because [20], by (Select) 20] Y >= Y by (Meta) 21] fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= /\x./\y.yap(F(x), y) because [22], by (F-Abs) 22] fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z, z) >= /\x.yap(F(z), x) because [23], by (F-Abs) 23] fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z, z, u) >= yap(F(z), u) because fold > yap, [24] and [29], by (Copy) 24] fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z, z, u) >= F(z) because [25], by (Select) 25] /\x.yap(F(fold*(/\y./\v.yap(F(y), v), cons(X, Y), Z, z, u)), x) >= F(z) because [26], by (Eta)[Kop13:2] 26] F(fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z, z, u)) >= F(z) because [27], by (Meta) 27] fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z, z, u) >= z because [28], by (Select) 28] z >= z by (Var) 29] fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z, z, u) >= u because [30], by (Select) 30] u >= u by (Var) 31] fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= Y because [32], by (Select) 32] cons(X, Y) >= Y because [19], by (Star) 33] fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= yap(F(Z), X) because fold > yap, [34] and [39], by (Copy) 34] fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= F(Z) because [35], by (Select) 35] /\x.yap(F(fold*(/\y./\v.yap(F(y), v), cons(X, Y), Z)), x) >= F(Z) because [36], by (Eta)[Kop13:2] 36] F(fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z)) >= F(Z) because [37], by (Meta) 37] fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= Z because [38], by (Select) 38] Z >= Z by (Meta) 39] fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= X because [40], by (Select) 40] cons(X, Y) >= X because [41], by (Star) 41] cons*(X, Y) >= X because [42], by (Select) 42] X >= X by (Meta) 43] sum(X) >= fold(/\x./\y.yap(add(x), y), X, _|_) because [44], by (Star) 44] sum*(X) >= fold(/\x./\y.yap(add(x), y), X, _|_) because sum > fold, [45], [53] and [55], by (Copy) 45] sum*(X) >= /\y./\z.yap(add(y), z) because [46], by (F-Abs) 46] sum*(X, x) >= /\z.yap(add(x), z) because [47], by (F-Abs) 47] sum*(X, x, y) >= yap(add(x), y) because sum > yap, [48] and [51], by (Copy) 48] sum*(X, x, y) >= add(x) because sum > add and [49], by (Copy) 49] sum*(X, x, y) >= x because [50], by (Select) 50] x >= x by (Var) 51] sum*(X, x, y) >= y because [52], by (Select) 52] y >= y by (Var) 53] sum*(X) >= X because [54], by (Select) 54] X >= X by (Meta) 55] sum*(X) >= _|_ by (Bot) 56] fold(mul, X, 1) >= X because [57], by (Star) 57] fold*(mul, X, 1) >= X because [58], by (Select) 58] X >= X by (Meta) 59] yap(F, X) >= @_{o -> o}(F, X) because [60], by (Star) 60] yap*(F, X) >= @_{o -> o}(F, X) because yap > @_{o -> o}, [61] and [62], by (Copy) 61] yap*(F, X) >= F because [11], by (Select) 62] yap*(F, X) >= X because [12], by (Select) 63] fold(F, X, Y) >= fold#(F, X, Y) because [64], by (Star) 64] fold*(F, X, Y) >= fold#(F, X, Y) because fold > fold#, [65], [67] and [69], by (Copy) 65] fold*(F, X, Y) >= F because [66], by (Select) 66] F >= F by (Meta) 67] fold*(F, X, Y) >= X because [68], by (Select) 68] X >= X by (Meta) 69] fold*(F, X, Y) >= Y because [70], by (Select) 70] Y >= Y by (Meta) 71] yap(F, X) >= #argfun-yap##(@_{o -> o}(F, X)) because [72], by (Star) 72] yap*(F, X) >= #argfun-yap##(@_{o -> o}(F, X)) because yap > #argfun-yap## and [73], by (Copy) 73] yap*(F, X) >= @_{o -> o}(F, X) because yap > @_{o -> o}, [74] and [76], by (Copy) 74] yap*(F, X) >= F because [75], by (Select) 75] F >= F by (Meta) 76] yap*(F, X) >= X because [77], by (Select) 77] X >= X by (Meta) By the observations in [Kop12, Sec. 6.6], this reduction pair suffices; we may thus replace the dependency pair problem (P_2, R_0, minimal, all) by (P_3, R_0, minimal, all), where P_3 consists of: yap#(F, X) =#> F(X) Thus, the original system is terminating if (P_3, R_0, minimal, all) is finite. We consider the dependency pair problem (P_3, R_0, minimal, all). We will use the reduction pair processor [Kop12, Thm. 7.16]. It suffices to find a standard reduction pair [Kop12, Def. 6.69]. Thus, we must orient: yap#(F, X) >? F(X) fold(/\x./\y.yap(F(x), y), nil, X) >= X fold(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= fold(/\z./\u.yap(F(z), u), Y, yap(F(Z), X)) sum(X) >= fold(/\x./\y.yap(add(x), y), X, 0) fold(mul, X, 1) >= prod(X) yap(F, X) >= F X yap(F, X) >= yap#(F, X) We apply [Kop12, Thm. 6.75] and use the following argument functions: pi( yap#(F, X) ) = #argfun-yap##(F X) Since this representation is not advantageous for the higher-order recursive path ordering, we present the strict requirements in their unextended form, which is not problematic since for any F, s and substituion gamma: (F s)gamma beta-reduces to F(s)gamma.) We use a recursive path ordering as defined in [Kop12, Chapter 5]. Argument functions: [[0]] = _|_ [[fold(x_1, x_2, x_3)]] = fold(x_2, x_1, x_3) [[prod(x_1)]] = x_1 We choose Lex = {fold} and Mul = {#argfun-yap##, 1, @_{o -> o}, add, cons, mul, nil, sum, yap, yap#}, and the following precedence: 1 > cons > mul > nil > sum > add > fold > yap > #argfun-yap## > @_{o -> o} > yap# Taking the argument function into account, and fixing the greater / greater equal choices, the constraints can be denoted as follows: #argfun-yap##(@_{o -> o}(F, X)) > @_{o -> o}(F, X) fold(/\x./\y.yap(F(x), y), nil, X) >= X fold(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= fold(/\x./\y.yap(F(x), y), Y, yap(F(Z), X)) sum(X) >= fold(/\x./\y.yap(add(x), y), X, _|_) fold(mul, X, 1) >= X yap(F, X) >= @_{o -> o}(F, X) yap(F, X) >= #argfun-yap##(@_{o -> o}(F, X)) With these choices, we have: 1] #argfun-yap##(@_{o -> o}(F, X)) > @_{o -> o}(F, X) because [2], by definition 2] #argfun-yap##*(@_{o -> o}(F, X)) >= @_{o -> o}(F, X) because [3], by (Select) 3] @_{o -> o}(F, X) >= @_{o -> o}(F, X) because @_{o -> o} in Mul, [4] and [5], by (Fun) 4] F >= F by (Meta) 5] X >= X by (Meta) 6] fold(/\x./\y.yap(F(x), y), nil, X) >= X because [7], by (Star) 7] fold*(/\x./\y.yap(F(x), y), nil, X) >= X because [8], by (Select) 8] X >= X by (Meta) 9] fold(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= fold(/\x./\y.yap(F(x), y), Y, yap(F(Z), X)) because [10], by (Star) 10] fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= fold(/\x./\y.yap(F(x), y), Y, yap(F(Z), X)) because [11], [14], [21] and [23], by (Stat) 11] cons(X, Y) > Y because [12], by definition 12] cons*(X, Y) >= Y because [13], by (Select) 13] Y >= Y by (Meta) 14] fold*(/\x./\y.yap(F(x), y), cons(X, Y), Z) >= /\x./\y.yap(F(x), y) because [15], by (Select) 15] /\x./\z.yap(F(x), z) >= /\x./\z.yap(F(x), z) because [16], by (Abs) 16] /\z.yap(F(y), z) >= /\z.yap(F(y), z) because [17], by (Abs) 17] yap(F(y), x) >= yap(F(y), x) because yap in Mul, [18] and [20], by (Fun) 18] F(y) >= F(y) because [19], by (Meta) 19] y >= y by (Var) 20] x >= x by (Var) 21] fold*(/\z./\u.yap(F(z), u), cons(X, Y), Z) >= Y because [22], by (Select) 22] cons(X, Y) >= Y because [12], by (Star) 23] fold*(/\z./\u.yap(F(z), u), cons(X, Y), Z) >= yap(F(Z), X) because fold > yap, [24] and [29], by (Copy) 24] fold*(/\z./\u.yap(F(z), u), cons(X, Y), Z) >= F(Z) because [25], by (Select) 25] /\z.yap(F(fold*(/\u./\v.yap(F(u), v), cons(X, Y), Z)), z) >= F(Z) because [26], by (Eta)[Kop13:2] 26] F(fold*(/\z./\u.yap(F(z), u), cons(X, Y), Z)) >= F(Z) because [27], by (Meta) 27] fold*(/\z./\u.yap(F(z), u), cons(X, Y), Z) >= Z because [28], by (Select) 28] Z >= Z by (Meta) 29] fold*(/\z./\u.yap(F(z), u), cons(X, Y), Z) >= X because [30], by (Select) 30] cons(X, Y) >= X because [31], by (Star) 31] cons*(X, Y) >= X because [32], by (Select) 32] X >= X by (Meta) 33] sum(X) >= fold(/\x./\y.yap(add(x), y), X, _|_) because [34], by (Star) 34] sum*(X) >= fold(/\x./\y.yap(add(x), y), X, _|_) because sum > fold, [35], [43] and [45], by (Copy) 35] sum*(X) >= /\y./\z.yap(add(y), z) because [36], by (F-Abs) 36] sum*(X, x) >= /\z.yap(add(x), z) because [37], by (F-Abs) 37] sum*(X, x, y) >= yap(add(x), y) because sum > yap, [38] and [41], by (Copy) 38] sum*(X, x, y) >= add(x) because sum > add and [39], by (Copy) 39] sum*(X, x, y) >= x because [40], by (Select) 40] x >= x by (Var) 41] sum*(X, x, y) >= y because [42], by (Select) 42] y >= y by (Var) 43] sum*(X) >= X because [44], by (Select) 44] X >= X by (Meta) 45] sum*(X) >= _|_ by (Bot) 46] fold(mul, X, 1) >= X because [47], by (Star) 47] fold*(mul, X, 1) >= X because [48], by (Select) 48] X >= X by (Meta) 49] yap(F, X) >= @_{o -> o}(F, X) because [50], by (Star) 50] yap*(F, X) >= @_{o -> o}(F, X) because yap > @_{o -> o}, [51] and [52], by (Copy) 51] yap*(F, X) >= F because [4], by (Select) 52] yap*(F, X) >= X because [5], by (Select) 53] yap(F, X) >= #argfun-yap##(@_{o -> o}(F, X)) because [54], by (Star) 54] yap*(F, X) >= #argfun-yap##(@_{o -> o}(F, X)) because yap > #argfun-yap## and [55], by (Copy) 55] yap*(F, X) >= @_{o -> o}(F, X) because yap > @_{o -> o}, [56] and [58], by (Copy) 56] yap*(F, X) >= F because [57], by (Select) 57] F >= F by (Meta) 58] yap*(F, X) >= X because [59], by (Select) 59] X >= X by (Meta) By the observations in [Kop12, Sec. 6.6], this reduction pair suffices; we may thus replace a dependency pair problem (P_3, R_0) by ({}, R_0). By the empty set processor [Kop12, Thm. 7.15] this problem may be immediately removed. As all dependency pair problems were succesfully simplified with sound (and complete) processors until nothing remained, we conclude termination. +++ Citations +++ [Kop12] C. Kop. Higher Order Termination. PhD Thesis, 2012. [Kop13:2] C. Kop. StarHorpo with an Eta-Rule. Unpublished manuscript, http://cl-informatik.uibk.ac.at/users/kop/etahorpo.pdf, 2013.