We consider universal computability of the LCTRS with only rule scheme Calc: Signature: cond :: Int -> Int -> Int -> Int if :: Bool -> Int -> Int -> Int min :: Int -> Int -> Int minus :: Int -> Int -> Int Rules: minus(x, x) -> 0 minus(x, y) -> cond(min(x, y), x, y) cond(y, x, y) -> 1 + minus(x, y + 1) min(u, v) -> if(u < v, u, v) if(true, u, v) -> u if(false, u, v) -> v The system is accessible function passing by a sort ordering that equates all sorts. We start by computing the initial DP problem D1 = (P1, R UNION R_?, f, c), where: P1. (1) minus#(x, y) => min#(x, y) (2) minus#(x, y) => cond#(min(x, y), x, y) (3) cond#(y, x, y) => minus#(x, y + 1) (4) min#(u, v) => if#(u < v, u, v) ***** We apply the Graph Processor on D1 = (P1, R UNION R_?, f, c). We compute a graph approximation with the following edges: 1: 4 2: 3 3: 1 2 4: There is only one SCC, so all DPs not inside the SCC can be removed. Processor output: { D2 = (P2, R UNION R_?, f, c) }, where: P2. (1) minus#(x, y) => cond#(min(x, y), x, y) (2) cond#(y, x, y) => minus#(x, y + 1) ***** We apply the Theory Arguments Processor on D2 = (P2, R UNION R_?, f, c). We use the following theory arguments function: cond# : [2, 3] minus# : [1, 2] Processor output: { D3 = (P3, R UNION R_?, f, c) ; D4 = (P4, R UNION R_?, f, c) }, where: P3. (1) minus#(x, y) => cond#(min(x, y), x, y) (2) cond#(y, x, y) => minus#(x, y + 1) { y, x } P4. (1) cond#(y, x, y) => minus#(x, y + 1) ***** We apply the Theory Arguments Processor on D3 = (P3, R UNION R_?, f, c). We use the following theory arguments function: cond# : [2, 3] minus# : [1, 2] Processor output: { D5 = (P5, R UNION R_?, f, c) ; D6 = (P6, R UNION R_?, f, c) }, where: P5. (1) minus#(x, y) => cond#(min(x, y), x, y) { x, y } (2) cond#(y, x, y) => minus#(x, y + 1) { y, x } P6. (1) minus#(x, y) => cond#(min(x, y), x, y) ***** We apply the Graph Processor on D4 = (P4, R UNION R_?, f, c). We compute a graph approximation with the following edges: 1: As there are no SCCs, this DP problem is removed. Processor output: { }. ***** No progress could be made on DP problem D5 = (P5, R UNION R_?, f, c).