We consider universal computability of the LCTRS with only rule scheme Calc:

  Signature: cond   :: Bool -> Int -> Int -> Int
             log    :: Int -> Int -> Int
             logNat :: Bool -> Int -> Int -> Int

  Rules: log(x, y) -> logNat(x >= 0 /\ y >= 2, x, y)
         logNat(true, x, y) -> cond(x <= y, x, y)
         cond(true, x, y) -> 1
         cond(false, x, y) -> 2 * log(x, y * y)

The system is accessible function passing by a sort ordering that equates all sorts.

We start by computing the initial DP problem D1 = (P1, R UNION R_?, f, c), where:

  P1. (1) log#(x, y) => logNat#(x >= 0 /\ y >= 2, x, y)
      (2) logNat#(true, x, y) => cond#(x <= y, x, y)
      (3) cond#(false, x, y) => log#(x, y * y)

***** We apply the Theory Arguments Processor on D1 = (P1, R UNION R_?, f, c).

We use the following theory arguments function:

  cond#   : [1, 2, 3]
  log#    : [1, 2]
  logNat# : [1, 2, 3]

Processor output: { D2 = (P2, R UNION R_?, f, c) ; D3 = (P3, R UNION R_?, f, c) }, where:

  P2. (1) log#(x, y) => logNat#(x >= 0 /\ y >= 2, x, y)
      (2) logNat#(true, x, y) => cond#(x <= y, x, y) { x, y }
      (3) cond#(false, x, y) => log#(x, y * y) { x, y }

  P3. (1) logNat#(true, x, y) => cond#(x <= y, x, y)
      (2) cond#(false, x, y) => log#(x, y * y)

***** We apply the Theory Arguments Processor on D2 = (P2, R UNION R_?, f, c).

We use the following theory arguments function:

  cond#   : [1, 2, 3]
  log#    : [1, 2]
  logNat# : [1, 2, 3]

Processor output: { D4 = (P4, R UNION R_?, f, c) ; D5 = (P5, R UNION R_?, f, c) }, where:

  P4. (1) log#(x, y) => logNat#(x >= 0 /\ y >= 2, x, y) { x, y }
      (2) logNat#(true, x, y) => cond#(x <= y, x, y) { x, y }
      (3) cond#(false, x, y) => log#(x, y * y) { x, y }

  P5. (1) log#(x, y) => logNat#(x >= 0 /\ y >= 2, x, y)

***** We apply the Graph Processor on D3 = (P3, R UNION R_?, f, c).

We compute a graph approximation with the following edges:

  1: 2 
  2:

As there are no SCCs, this DP problem is removed.

Processor output: { }.

***** No progress could be made on DP problem D4 = (P4, R UNION R_?, f, c).